Burglars are pushing, with a horizontal force Fpush, a safe of mass m and coefficient of kinetic friction μk up a slope of angle θ. What is the safe's acceleration (in abstract terms)?
as= +/-gsinθ (natural accl down a slope)
friction on a slope= μmgcosθ
The Attempt at a Solution
Fnet= Force up the slope- natural accl down - kinetic friction
Fnet= Fcosθ - mgsinθ - μmgcosθ
ma= Fcosθ - mgsinθ - μmgcosθ
a= Fcosθ/m - gsinθ - μgcosθ
I thought this was right but we have numbers to plug in to check for correctness:
coeff of kf= 0.20
and acceleration is supposed to be 1.777 m/s2
I can't seem to arrive at this answer.