How Far Can a Greased Watermelon Be Pulled Down an Inclined Plane?

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Homework Help Overview

The problem involves a greased watermelon on an inclined plane, where participants are exploring the forces acting on the watermelon, including friction and spring force, to determine how far it can be pulled down the ramp without moving back up.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculations involving forces, particularly the role of static friction and the direction of the friction force. There is a focus on whether the watermelon is on the verge of slipping up or down the slope.

Discussion Status

There is an ongoing examination of the assumptions regarding the direction of the friction force and its implications on the calculations. Some participants have revised their answers based on this discussion, indicating a productive exploration of the problem.

Contextual Notes

Participants are considering the effects of the coefficients of friction and the spring constant in their calculations, while also questioning the initial conditions of the problem regarding the motion of the watermelon.

Jpyhsics
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Homework Statement


As part of an elaborate prank, a well-greased watermelon (m=4.72 kg) is placed on a ramp inclined with angle θ=27.4° with respect to the horizontal. Because of the grease, the coefficients of static and kinetic friction are µs= 0.560 and µk= 0.392 respectively. The watermelon is attached to the wall, parallel to the ramp, by a spring with constant k=175.2 N/m. What is the farthest distance down the ramp that the watermelon can be pulled away from the spring equilibrium and placed at rest on the surface without the spring pulling the watermelon back up the ramp? Express your answer in metres

Homework Equations


F=ma

The Attempt at a Solution


ΣFx=mgSinθ-kx-μsmgCosθ

Rearranged to make:
x=(mg(μsCosθ-Sinθ))/(-k)
x=-0.00977m

I used the coefficient of static friction, because it was at rest. Does my solution look correct?
I have included an image of my solution as well.
 

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Hello.

Does a negative answer for x seem right?

Check to see if you have the correct direction for the friction force.
 
TSny said:
Hello.

Does a negative answer for x seem right?

Check to see if you have the correct direction for the friction force.
Why would force of friction be towards the right?
 
Jpyhsics said:
Why would force of friction be towards the right?
According to the conditions stated in the problem, is the watermelon on the verge of slipping up the slope or slipping down the slope?
 
TSny said:
According to the conditions stated in the problem, is the watermelon on the verge of slipping up the slope or slipping down the slope?
Slipping up...oh so the friction has to oppose that verge of motion? My revised answer is 0.253m Does that seem right? And thank you so much!
 
Jpyhsics said:
Slipping up...oh so the friction has to oppose that verge of motion? My revised answer is 0.253m Does that seem right? And thank you so much!
Looks right to me.
 

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