AC circuit steady state expression

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In an AC circuit at steady state, a capacitor acts as a short circuit while an inductor behaves like an open circuit. However, this does not imply that the overall circuit response is zero, as the impedance of these components varies with frequency. The characteristics mentioned are specific to DC steady state conditions. Understanding the frequency-dependent behavior of capacitors and inductors is crucial for analyzing AC circuits. Therefore, the steady state analysis for AC circuits requires consideration of impedance rather than simply categorizing components as open or short.
pyroknife
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I know that in an AC circuit at the steady state a capacitor behaves like a short and inductor behaves like an open. Since the inductor is open wouldn't that just mean the answer is 0?
 

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pyroknife said:
I know that in an AC circuit at the steady state a capacitor behaves like a short and inductor behaves like an open. Since the inductor is open wouldn't that just mean the answer is 0?

No, those characteristics apply to DC steady state for those components. For AC, the components exhibit impedance that depends upon frequency.
 

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