AC circuit steady state expression

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 5K views
pyroknife
Messages
611
Reaction score
4
I know that in an AC circuit at the steady state a capacitor behaves like a short and inductor behaves like an open. Since the inductor is open wouldn't that just mean the answer is 0?
 

Attachments

  • Untitled.png
    Untitled.png
    14.2 KB · Views: 641
Physics news on Phys.org
pyroknife said:
I know that in an AC circuit at the steady state a capacitor behaves like a short and inductor behaves like an open. Since the inductor is open wouldn't that just mean the answer is 0?

No, those characteristics apply to DC steady state for those components. For AC, the components exhibit impedance that depends upon frequency.