What Are the Initial and Steady State Values in an SPST Switched RLC Circuit?

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Discussion Overview

The discussion revolves around analyzing an SPST switched RLC circuit, specifically focusing on determining the initial and steady-state values of voltage and current across the capacitor and inductor. The scope includes homework-related problem-solving and circuit analysis.

Discussion Character

  • Homework-related
  • Technical explanation

Main Points Raised

  • One participant states that at t=0-, the capacitor acts like an open circuit and the inductor like a short circuit, leading to vC(0-) = 12V and iL(0-) = 0.
  • At t=0, the same participant suggests that the capacitor behaves like a voltage source and the inductor like a current source of 0A, questioning if iC(0) would be -3A and stating vL(0) = 12V.
  • For t=infinity, the participant claims that the capacitor acts like an open circuit and the inductor like a short circuit, concluding that vC(infinity) = 0V and iL(infinity) = 4A.
  • Another participant expresses agreement with the initial analysis, stating "Looks right to me."
  • Subsequent posts seek further validation of the initial participant's claims, with one participant affirming the correctness of the answers provided.

Areas of Agreement / Disagreement

There appears to be general agreement on the initial analysis, as some participants confirm the correctness of the values presented. However, the discussion does not explore any alternative viewpoints or corrections, leaving some aspects potentially unresolved.

Contextual Notes

Assumptions regarding the behavior of the capacitor and inductor at different time intervals are made, but the discussion does not delve into the underlying principles or any mathematical derivations that may support these claims.

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Homework Statement


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SPST switch closes at t=0. Find vC(0-) and iL(0-), iC(0) and vL(0), and vC(infinity) and iL(infinity).

Homework Equations


The Attempt at a Solution


kind of basic circuit, i know, but i just wanted to check my answers in case i did something wrong.

At t=0- : capacitor acts like open circuit, inductor like short circuit. also there no closed loops, so there's no current. vC(0-)=V(s)=12V, and iL(0-)=0.

at t=0: capaciator behaves like voltage source, inductor like current source of 0A. so would iC(0) be -3A? and vL(0)=12V.

at t=infinity: capacitor acts like open circuit, inductor like short circuit. vC(infinity)=0V, and iL(infinity)=4A.
 
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Looks right to me
 
anyone else?? did i do this right?
 
asdf12312 said:
anyone else?? did i do this right?

Yes you did.
 

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