AC Theory Question: Transformers

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SUMMARY

The discussion focuses on performing a short circuit test on a 40-kVA 4800/240V 60Hz transformer, where the impedance (Ze) is calculated to be 7.92<64 ohms based on a voltage of 66V and a rated current. The user seeks to determine the percent voltage regulation with a 0.88 lagging power factor load and is confused about calculating the load impedance (ZL) and current (I). The short circuit test involves shorting the load impedance to isolate Ze, and the assumption is made that the source has no internal resistance.

PREREQUISITES
  • Understanding of transformer operation and short circuit testing
  • Familiarity with impedance calculations in AC circuits
  • Knowledge of power factor and its implications in electrical circuits
  • Ability to interpret phasor diagrams and power triangles
NEXT STEPS
  • Learn how to calculate percent voltage regulation in transformers
  • Study the principles of short circuit testing in electrical engineering
  • Explore the concept of load impedance (ZL) and its calculation
  • Investigate the relationship between current, voltage, and impedance in AC circuits
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Electrical engineering students, transformer technicians, and professionals involved in power systems analysis and design will benefit from this discussion.

Ryan231
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Question: A short circuit test is performed on the low voltage side of a 40-kVA 4800/240V 60HZ transformer and the following data are obtained: W = 240W, V= 66V, and I = rated current. Determine the percent voltage regulation with a 0.88 lagging PowerFactor load connected.

On the Short cct test I found
Impendence (Ze) to be = 7.92<64 ohms

Basically now we've got a simple series circuit with
Source = 4800V
Ze = 7.92<64 ohms
ZL = x< -28.4 ohms

I'm totally stuck on how to find either the current (I) or the magnitude of ZL (x). If I could find either of these I could solve the voltage drop acrossed ZL and find the VR.
 
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Sorry for my dumb question, but how do you perform this short circuit test? Is the 66V the input voltage when the output is shorted? What is the assumed source impedance for the 240VAC mains feeding the transformer during this short circuit test?
 
berkeman said:
Sorry for my dumb question, but how do you perform this short circuit test? Is the 66V the input voltage when the output is shorted? What is the assumed source impedance for the 240VAC mains feeding the transformer during this short circuit test?

The short cct test is just shorting out the Load Impedence (ZL) this allows us to isolate Ze and calculate it by doing:

Ze=V/I = 66/8.33 = 7.92
To find the angle we break Ze down into Re (resistance Equivilant) and Xe (inductive). cosX = re/xe = 64 degrees.
We found these values using the power triangle.

The 66v tells us the amount of voltage the circuit uses I guess.

I'm not sure what you mean by the last part, but we assume the sources are perfect for these questions (ie no internal resistance).

The final circuit looks like this

Source 4800VAC (no internal resistance)
Load Ze = 7.92<64 ohms
Load ZL = x< -28.4 ohms

This is where I am stuck how can I find the current when all I have is a source voltage and 1 of the 2 loads?

Also, the teacher mentioned that he may give us the current of the circuit WITHOUT the angle, how would I go about finding the angle of the current?
 
Last edited:

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