AC Theory Question: Transformers

AI Thread Summary
The discussion revolves around performing a short circuit test on a transformer to determine voltage regulation with a specific load. The impedance (Ze) was calculated as 7.92<64 ohms, but the user is struggling to find the load impedance (ZL) and the current (I) necessary for further calculations. Clarifications were provided that the 66V represents the voltage during the short circuit test and that source impedances are typically assumed to be negligible for these calculations. The user seeks guidance on how to calculate current with the given source voltage and one load impedance, as well as how to determine the angle of the current if only the magnitude is provided. Understanding these concepts is crucial for accurately assessing transformer performance under load conditions.
Ryan231
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Question: A short circuit test is performed on the low voltage side of a 40-kVA 4800/240V 60HZ transformer and the following data are obtained: W = 240W, V= 66V, and I = rated current. Determine the percent voltage regulation with a 0.88 lagging PowerFactor load connected.

On the Short cct test I found
Impendence (Ze) to be = 7.92<64 ohms

Basically now we've got a simple series circuit with
Source = 4800V
Ze = 7.92<64 ohms
ZL = x< -28.4 ohms

I'm totally stuck on how to find either the current (I) or the magnitude of ZL (x). If I could find either of these I could solve the voltage drop acrossed ZL and find the VR.
 
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Sorry for my dumb question, but how do you perform this short circuit test? Is the 66V the input voltage when the output is shorted? What is the assumed source impedance for the 240VAC mains feeding the transformer during this short circuit test?
 
berkeman said:
Sorry for my dumb question, but how do you perform this short circuit test? Is the 66V the input voltage when the output is shorted? What is the assumed source impedance for the 240VAC mains feeding the transformer during this short circuit test?

The short cct test is just shorting out the Load Impedence (ZL) this allows us to isolate Ze and calculate it by doing:

Ze=V/I = 66/8.33 = 7.92
To find the angle we break Ze down into Re (resistance Equivilant) and Xe (inductive). cosX = re/xe = 64 degrees.
We found these values using the power triangle.

The 66v tells us the amount of voltage the circuit uses I guess.

I'm not sure what you mean by the last part, but we assume the sources are perfect for these questions (ie no internal resistance).

The final circuit looks like this

Source 4800VAC (no internal resistance)
Load Ze = 7.92<64 ohms
Load ZL = x< -28.4 ohms

This is where I am stuck how can I find the current when all I have is a source voltage and 1 of the 2 loads?

Also, the teacher mentioned that he may give us the current of the circuit WITHOUT the angle, how would I go about finding the angle of the current?
 
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