# Acceleration across a floor with friction

1. Jul 19, 2011

### djokoman95

1. The problem statement, all variables and given/known data

A man pushes a box full of toys that has a mass of 12kg across a floor with a force of 60 N. The box of toys and the floor have a kinetic coefficient of friction of 0.5.
What is the acceleration of the box?

2. Relevant equations
F=ma

3. The attempt at a solution

Here's what I have so far. f$\mu$k=12*9.8*0.5=58.8. So, since the man is pushing with 60 N of force, and the friction force is pushing back with 58.8 N, he is pushing the box with a net force of .2 N. I think, but I"m not sure, that I could just use this 0.2 as the F in F=ma, then solve for a, using 12 as m, and 0.2 as F. I'm not quite sure if this is correct though.

2. Jul 19, 2011

### azureth

Yes,it is correct.

3. Jul 19, 2011

### gdbb

It's not 0.2 N, it's 1.2 N :)

4. Jul 20, 2011

### cupid.callin

1.2 is the net force
and according to newton's laws its equal to ma ...

5. Jul 20, 2011

### GreenPrint

Always draw a free body diagram if your not sure if your correct or not. If you do so you would see that your correct.