Acceleration and Deacceleration

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SUMMARY

The discussion focuses on calculating acceleration and deceleration in two scenarios: a bullet exiting a rifle barrel and a driver overtaking a slow-moving vehicle. The bullet's acceleration, calculated using the formula v² = u² + 2ax, results in 1,000,000 m/s², which is confirmed as reasonable for such high-speed projectiles. For the driver, who decelerates at -4 m/s² and overtakes a vehicle in 5 seconds, the same formula applies to determine the speeds of both vehicles at the moment of overtaking.

PREREQUISITES
  • Understanding of kinematic equations, specifically v² = u² + 2ax
  • Basic knowledge of acceleration and deceleration concepts
  • Familiarity with units of measurement in physics (m/s, m/s²)
  • Concept of constant acceleration in motion
NEXT STEPS
  • Study advanced kinematic equations for varying acceleration scenarios
  • Explore the physics of projectile motion and its implications in real-world applications
  • Learn about the effects of air resistance on bullet trajectories
  • Investigate real-world examples of deceleration in automotive physics
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Physics students, automotive engineers, and anyone interested in the dynamics of motion and acceleration calculations.

pippintook
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A bullet leaves the barrel of a rifle at 1000 m/s. If the gun barrel is 50 cm long, what is the acceleration of the bullet?

For this problem, I used v^2 = u^2 + 2ax, but got like 1000000 m/s^2 for my answer. Is this right? It seems like a ridiculous solution.



A driver sees a slow moving vehicle 100 meters ahead. He de-accelerates at -4 m/s^2. He overtakes the vehicle 5 seconds later. Given that the faster vehicle is now going half its original speed, what is the speed of each vehicle as the faster vehicle passes?

For this one, do I use the same formula or should I use another one?
 
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pippintook said:
A bullet leaves the barrel of a rifle at 1000 m/s. If the gun barrel is 50 cm long, what is the acceleration of the bullet?

For this problem, I used v^2 = u^2 + 2ax, but got like 1000000 m/s^2 for my answer. Is this right? It seems like a ridiculous solution.
If you assume constant acceleration then your solution is correct. 1x106 m/s2 is not unreasonable for the acceleration of a bullet.
pippintook said:
A driver sees a slow moving vehicle 100 meters ahead. He de-accelerates at -4 m/s^2. He overtakes the vehicle 5 seconds later. Given that the faster vehicle is now going half its original speed, what is the speed of each vehicle as the faster vehicle passes?

For this one, do I use the same formula or should I use another one?
That formula should be fine.
 

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