Acceleration and distance :S ?

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Homework Help Overview

The problem involves a scenario where a stone is dropped into a pit, and the time taken for the sound of the stone hitting the bottom to reach the person is given. The context includes the effects of gravity and the speed of sound, with a specific temperature affecting the sound's velocity.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the phases of the stone's fall and the sound's travel time, questioning the role of temperature in determining sound velocity. There are attempts to relate acceleration and distance, with some participants expressing uncertainty about how acceleration affects the distance calculation.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problem, including the equations of motion and the relationship between time, distance, and velocity. Some guidance has been offered regarding the phases of the motion, but no consensus has been reached on the final approach to finding the depth.

Contextual Notes

Participants are considering the effects of gravity and sound propagation, with some questioning the assumptions made about the instantaneous transition when the stone hits the bottom. The impact of temperature on sound velocity is also under discussion.

simply_me_xo
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ok so here's the question

She picks up a large stone and drops it into a pit, listening for the sound of it hitting the bottom. The pit has a uniform temperature of 8 degrees celsius. From the time the rock leaves her hadn to the time the sound of it striking bottom reachers her ears, 24 seconds pass. What is the depth of this whole?



... okay so i know that acceleration is change in velocity over time.
this gives you the time , and also the temperature which by using v=332+0.6(T) will give me a velocity

i'm assuming that the initial velocity would be 0 ? ... and then using the formula above the other velocity would be 336.8 m/s

thennnnnn do 336.8 divided by time ( 24 s ) so get acceleration ... but then how do i get the distanceee?

d=t*v butttt wouldn't acceleration effect that somehow?
 
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you have two phases in the system:

phase 1. the stone is falling in free fall state (if we neglect the air friction), takes it some time

-transition- the stone hits the bottom, this transition does not take time (assume it is instantaneous)

phase 2. the sound propagates from the bottom to the ears of the girl

now the total time (24s) is the sum of durations of phase 1 & phase 2

- I hope this helps you

BTW, i don't see what does the temperature do here, unless you considering the velocity propagation of sound in air as funtion of temperature (which i doubt in such situation)
 
Last edited:
thanksss , i don't seee how that gets me the depth of the whole though ?
 
Write an equation for the depth.
 
like just d=v*t
doesnt the acceleration effect that somehow though?
 
ok, let's see more in details

phase 2- speed of sound in air Vs = 1200 m/s = d / t2 , so t2 = Vs / d, also d = Vs t2

phase 1- gravity is the only force applied,
F=m a = m G, so G = a = dv/dt =d²y/dt², so v(t) = G t + V(0), so y(t) = G t² / 2 + v(0)t + y(0)
if you consider v(0) = 0 & y(0)=0, then y(t) = G t² / 2
then at the time of the impact (which is t1), y(t1) = d

so G t1² / 2 = d
or d = Vs t2

and also t1 + t2 = 24 seconds

the rest is clear
 

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