Acceleration as a function of position, and time taken to travel a distance

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Homework Help Overview

The discussion revolves around a problem in classical mechanics, specifically focusing on the relationship between acceleration, position, and time taken to travel a distance under gravitational influence. The original poster seeks to determine the time required for a body to move from a certain distance to the origin, given its initial acceleration as a function of position.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formulation of the acceleration as a function of position and explore integration techniques to derive relationships between velocity and position. There are questions about the completeness of the integration process and the handling of constants of integration.

Discussion Status

Some participants have provided guidance on integration methods and have shared their own attempts at solving the problem. There is an ongoing exploration of different interpretations of the integration steps and the implications of missing constants.

Contextual Notes

Participants are working under the constraints of a homework problem, which may limit the information available and the assumptions that can be made about the system. The original poster's initial conditions and the specific form of acceleration are central to the discussion.

jmz34
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I've been doing a problem that requires me to find the time taken to travel a certain distance if I know the initial acceleration of a body at the starting position and its initial velocity (starts from rest). The acceleration is a function of position a=-GM/(Ro^2).

So say a body is released from rest a distance Ro from a point mass, and it's initial acceleration is that stated above- how would I go about finding the time taken to travel this distance (from Ro to the origin.


Thanks.
 
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hi jmz34! :wink:

so r'' = -GM/r2 ?

multiply both sides by r' …

r'r'' = -GMr'/r2

… and integrate :smile:
 
tiny-tim said:
hi jmz34! :wink:

so r'' = -GM/r2 ?

multiply both sides by r' …

r'r'' = -GMr'/r2

… and integrate :smile:

Using this method I did this:

d/dt(0.5*(r')^2)=(-GM/r^2)r'

then integrated once and simplified to get

(dr/dt)^2=2GM/r

solving this for t gives:

t=(1/3)*SQRT(2/GM)*Ro^(3/2)

If you could have a quick look at my method I'd be very grateful.

Thanks a lot.
 
jmz34 said:
Using this method I did this:

d/dt(0.5*(r')^2)=(-GM/r^2)r'

then integrated once and simplified to get

(dr/dt)^2=2GM/r.

yes, but after that i get a bit lost …

you seem to have lost r completely, and you don't have a constant of integration :confused:
 

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