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so I have this assignment where we have to get the dt and vt graphs of a bouncing basketball using a motion detector. the detector is facing down above the initial height of the ball, and is always above the ball facing down. so on my dt graph, the highest point is the ground. k so I have to find the acceleration due to gravity by finding the slope of the vt graph, here's where im confused. since the positive direction in the vt graph is bouncing down to the ground, and the negative direction is coming back up to the motion detector, is it -9.8 or +9.8. Please Please please explain how, im so confused. I thought it's always -9.8, but yea i dnt understand. im in gr.11 btw. THANK YOU SO MUCH FOR ANY HELP! PLEASE REPLY ASAP! (:

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