What is the acceleration of objects falling on the moon in a vacuum?

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Objects falling on the moon in a vacuum experience the same constant acceleration due to gravity, which is approximately 1.6 m/s², significantly less than Earth's 9.8 m/s². This means that all objects, regardless of their mass, will fall at the same rate when air resistance is negligible. The confusion arises between the concepts of constant speed and constant acceleration; while speed increases, the acceleration remains constant. Therefore, the correct understanding is that objects fall with a constant acceleration rather than an increasing or decreasing one. This principle aligns with the behavior of falling objects on Earth, where gravity dictates the same constant acceleration near the surface.
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Ok the question I have is pretty simple

we claimed thatif the air resistance could be neglected all objects on hte moon wuld fall at
a. the same constant speed
b. an increasing acceleration
c. the same constant acceleration
d. a decreasing acceleration

Ok so i know its not the same constant speed, because the acceleration is what changes. And I know the acceleration isn't decreasing, or it would be getting slower and stop mid air...which obviously doesn't happen. So I'm torn between b and c, an increasing acceleration and the same constant acceleration. If we use the rule that gravity pulls us 10 m/s-squared then it would have the same acceleration the whole time and the velocity would increase, so the answer has to be c right?

...ok now that I'm confused hopefully someone agrees with me or can explain why that's wrong.
 
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As long as we are only talking about objects near the moon's surface, then they all fall with the same acceleration--for the same reason that falling objects near the Earth's surface all have the same acceleration (ignoring air resistance). The acceleration due to gravity near the Earth's surface is about 10 m/s^2. Would you expect the acceleration due to gravity on the moon to be the same? smaller? greater?
 
I agree with you. That is assuming that the object is at small distances wrt the moons radius.

EDIT: Beaten to it by a better explanation.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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