# Acceleration. linear motion. i'm stuck

1. Dec 11, 2008

### Run Haridan

acceleration. linear motion. i'm stuck!!!

1. The problem statement, all variables and given/known data
a train moves at a velocity of 60 m s-1 and stops after a distance of 600m. what is its deceleration?

2. Relevant equations
v=s/t

3. The attempt at a solution
this is my working:
u= 0 m s-1
v= 60 m s-1
s= 600 m

v=s/t
60=600/t
t=10 s

Last edited: Dec 12, 2008
2. Dec 11, 2008

### rl.bhat

Re: acceleration. linear motion. i'm stuck!!!

The velocity is not uniform. So you can't use v = s/t. And here initial velocity is 60 m/s and final velocity is 0. Use appropriate kinamatic formula which relates initial velocity, final velocity , acceleration and displacement.

3. Dec 12, 2008

### Run Haridan

Re: acceleration. linear motion. i'm stuck!!!

what formula? tell me and i'll try to work it out!

4. Dec 12, 2008

### rl.bhat

Re: acceleration. linear motion. i'm stuck!!!

v^2 - u^2 = 2as

5. Dec 12, 2008

### harvellt

Re: acceleration. linear motion. i'm stuck!!!

My favorite for finding acceleration is a($$\Delta$$x)=(1/2)($$\Delta$$V2)