Acceleration. linear motion. i'm stuck

  • #1
acceleration. linear motion. i'm stuck!!!

Homework Statement


a train moves at a velocity of 60 m s-1 and stops after a distance of 600m. what is its deceleration?


Homework Equations


v=s/t



The Attempt at a Solution


this is my working:
u= 0 m s-1
v= 60 m s-1
s= 600 m

v=s/t
60=600/t
t=10 s

...and i'm stuck here. please help!!!
 
Last edited:

Answers and Replies

  • #2
rl.bhat
Homework Helper
4,433
7


The velocity is not uniform. So you can't use v = s/t. And here initial velocity is 60 m/s and final velocity is 0. Use appropriate kinamatic formula which relates initial velocity, final velocity , acceleration and displacement.
 
  • #3


what formula? tell me and i'll try to work it out!
 
  • #4
rl.bhat
Homework Helper
4,433
7


v^2 - u^2 = 2as
 
  • #5
90
0


My favorite for finding acceleration is a([tex]\Delta[/tex]x)=(1/2)([tex]\Delta[/tex]V2)
 

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