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Acceleration. linear motion. i'm stuck

acceleration. linear motion. i'm stuck!!!

1. Homework Statement
a train moves at a velocity of 60 m s-1 and stops after a distance of 600m. what is its deceleration?


2. Homework Equations
v=s/t



3. The Attempt at a Solution
this is my working:
u= 0 m s-1
v= 60 m s-1
s= 600 m

v=s/t
60=600/t
t=10 s

...and i'm stuck here. please help!!!
 
Last edited:

rl.bhat

Homework Helper
4,433
5
Re: acceleration. linear motion. i'm stuck!!!

The velocity is not uniform. So you can't use v = s/t. And here initial velocity is 60 m/s and final velocity is 0. Use appropriate kinamatic formula which relates initial velocity, final velocity , acceleration and displacement.
 
Re: acceleration. linear motion. i'm stuck!!!

what formula? tell me and i'll try to work it out!
 

rl.bhat

Homework Helper
4,433
5
Re: acceleration. linear motion. i'm stuck!!!

v^2 - u^2 = 2as
 
90
0
Re: acceleration. linear motion. i'm stuck!!!

My favorite for finding acceleration is a([tex]\Delta[/tex]x)=(1/2)([tex]\Delta[/tex]V2)
 

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