Acceleration of 3.8kg Object: 110.58 m/s2, 28.66°

  • Thread starter Thread starter wallace13
  • Start date Start date
  • Tags Tags
    Law Newton's law
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
Sign up Log in
1 reply · 1K views
wallace13
Messages
31
Reaction score
0
Only two forces act on an object (mass= 3.8 kg). One force is pointing east with 40 N. The other has a force of 75.0 N at a 45 degree angle. Find the magnitude and direction (relative to the x-axis) of the acceleration of the object.



pythagorean theorum
tan O= opp/adj



x y
53.03 53.03 < ---- found using 75sin45
40 0

= 97.03, 53.03 <--- resultant

pythagorean theorum with resultants = 110.58m/s
angle from tangent= 28.66 degrees
 
Physics news on Phys.org

Discussion

Hi wallace13,

wallace13 said:
Only two forces act on an object (mass= 3.8 kg). One force is pointing east with 40 N. The other has a force of 75.0 N at a 45 degree angle. Find the magnitude and direction (relative to the x-axis) of the acceleration of the object.



pythagorean theorum
tan O= opp/adj



x y
53.03 53.03 < ---- found using 75sin45
40 0

= 97.03, 53.03 <--- resultant

I believe that the 97.03 is incorrect.