Acceleration of a box across a rough horizontal plane

[Confusedbiomedeng]

Not sure if I'm doing this right would love input

Consider a box m=50kg which is being pulled on a rough, horizontal surface by a person using a rope . Assume that the person is applying a force of T=150N on the block , the rope makes an angle of 30 degrees with the horizontal and the coefficient of kinetic friction between the block and the horizontal surface is 0.2
Determine acceleration of the block if the block remains in full contact with the floor

Fx=FCosθ
Fx=150(Cos30)
Fx=129.9N

Fy=FSinθ
Fy=150(sin30)
Fy=75N

Fk=μFN
FN=mg-fy
FN=50(9.81)-75
FN=415.5

FK=0.2(415.5)
FK=83.1

Fnet=Fx-Fk
Fnet=129.9-83.1
Fnet=46.8=ma=50(a)=46.8
a=0.936m/s

 

[TSny]

It all looks good to me (except something's missing in the last symbol of the last line ).