1. The problem statement, all variables and given/known data A particle (mass = 2.0 mg, charge = -6.0 μC) moves in the positive direction along the x axis with a velocity of 3.0 km/s. It enters a magnetic field of (2i + 3j + 4k) mT. What is the acceleration of the particle in component form? 2. Relevant equations F = q(vXB) F = ma 3. The attempt at a solution First convert all values to SI units: mass = 0.002 kg q = -6x10^-6 C v = 3000 i m/s B = (0.002i + 0.003j + 0.004k) T Find vXB: vXB = -12j + 9k Plug vXB and q into F = q(vXB) and find a: F = (-6x10^-6)(-12j + 9k) = ma a = (7.2x10^-5 j - 5.4X10^-5 k) / 0.002 a = 0.036j - 0.027k m/s^2 However the correct answer provided to me is: (36j - 27k) m/s^2 I think i made a mistake converting the units for B from mT to T. i'm not sure how to convert units for vector components.