haruspex said:
What if I modify the question a little bit, find the acceleration 2 seconds after the wire is cut?
This is what I have in my mind:
The m
4 will push the right spring so the new extension (x
3) will be less than x
2 and all the other masses will move.
The extension on left spring does not change (still x
1) because the left spring, m
1 and m
2 will move as one system so the acceleration of m
1 and m
2 will be the same.
This means that the left spring will behave just like an inelastic string.
The magnitude of a
1, a
2 and a
3 will always be the same but all the acceleration, including a
4 won't be constant because there is continuous change in the extension of right spring, therefore there is continuous change in restoring force and there is continuous change in resultant force.
Am I correct?
If yes, how to set up equation of m
4 to account for continuous change in acceleration?
Thanks