Acceleration on the Moon: How Does Gravity Affect Objects?

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The discussion focuses on the effects of gravity on acceleration of objects on the Moon. The initial calculations incorrectly equated the acceleration due to gravity with the acceleration of a ball affected by a spring force. It was clarified that the forces acting on the ball are in opposite directions, leading to a misunderstanding of the problem. The correct approach involves using the formula ∑F = ma to analyze the forces more accurately. Understanding the distinction between gravitational acceleration and the acceleration from other forces is crucial for solving the problem correctly.
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Homework Statement


1.JPG


Homework Equations


F=ma

The Attempt at a Solution


I know it's either B or D

Weight = mg so let's say mass of ball is 11kg and gravity on moon is 6, so weight would be 66N

since acceleration a = F/m and we can say that F=mg

therefore a = mg / m which leaves: a=g

and because on the moon the gravity is less this means acceleration is less...yet this is wrong and the answer is D??
 
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You calculated the acceleration due to gravity, not the acceleration of the ball due to the force of the spring. One acts downward and the other upward.
 
Janus said:
You calculated the acceleration due to gravity, not the acceleration of the ball due to the force of the spring. One acts downward and the other upward.

Yep, I completely glossed over that, thanks.

Intuitively it makes sense now, but is there a formula I can use to get a better understanding?
 
ravsterphysics said:
Yep, I completely glossed over that, thanks.

Intuitively it makes sense now, but is there a formula I can use to get a better understanding?
∑F = ma
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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