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The acceleration of a car traveling around a sharp curve at a constant speed of 60 km/h differs from that of a car navigating a gentle curve at the same speed. This difference arises because the rate of change in direction is greater for a sharp turn, resulting in higher centripetal acceleration. The relevant formula for calculating this acceleration is ac = v2/r, where v is the velocity and r is the radius of the curve. As the radius decreases with sharper turns, the acceleration increases, leading to a higher risk of losing traction.
PREREQUISITESPhysics students, automotive engineers, and anyone interested in the dynamics of vehicle motion and safety during turns.
BOYLANATOR said:You are correct. There is an equation you could use to confirm your answer. If you assume that while the car travels around the bend it is briefly in circular motion, what formula could you use to describe the acceleration?
Would the radius become smaller making the acceleration larger? Correct me if I'm wrongBOYLANATOR said:The first one looks good. Can you see what would happen to the variables in that equation if the corner became sharper?
There would be less friction to keep the car on the road, making the car crash.BOYLANATOR said:Yes. For a bonus, why is the car more likely to slide off the road and crash on the sharper bend?
Ok got it! Thanks for the help!BOYLANATOR said:Right idea, but there's no real reason for the friction to decrease, it's more likely to remain constant...