1. The problem statement, all variables and given/known data The acceleration of a particle is directl porportional to the square of the time t. When t=0s, and the particle is at x=24m. Knowing that at t=6s, x=96m, and V=18m/s, express x and v in terms of t. 2. Relevant equations a=t2 3. The attempt at a solution so i took the integral of a=t2 and got v=1/3t3+C, then took the integral again to obtain x=1/12t4+Ct+A. So then I plugged in x=24 and t=0 to get A=24 so now my eqation is..... x=1/12t4+Ct+24 solving for C i get C=-6 so then my equation is x=1/12t4-6t+24 in the book the answer is 1/108t4+10t+24 what am I doing wrong?