(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The acceleration of a particle is directl porportional to the square of the time t. When t=0s, and the particle is at x=24m. Knowing that at t=6s, x=96m, and V=18m/s, express x and v in terms of t.

2. Relevant equations

a=t^{2}

3. The attempt at a solution

so i took the integral of a=t^{2}and got v=1/3t^{3}+C, then took the integral again to obtain x=1/12t^{4}+Ct+A.

So then I plugged in x=24 and t=0 to get A=24

so now my eqation is.....

x=1/12t^{4}+Ct+24 solving for C i get C=-6

so then my equation is x=1/12t^{4}-6t+24 in the book the answer is 1/108t^{4}+10t+24

what am I doing wrong?

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# Homework Help: Acceleration, velcocity, and position

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