Accerleration from power, mass & speed

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SUMMARY

The maximum acceleration of a car with a mass of 1200 kg and a maximum power output of 50 kW traveling at 60 mph is calculated to be 1.6 m/s². This is derived using the equations P = Fv and F = ma, leading to the formula a = P/mv. The conversion from mph to m/s is accurately performed, confirming the calculation is correct.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Knowledge of power and its relationship to force and velocity (P = Fv)
  • Ability to convert units from mph to m/s
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation of the equations P = Fv and F = ma
  • Learn about unit conversions, specifically between mph and m/s
  • Explore the implications of maximum power output on vehicle performance
  • Investigate real-world applications of acceleration calculations in automotive engineering
USEFUL FOR

Students in physics or engineering courses, automotive engineers, and anyone interested in vehicle dynamics and performance calculations.

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Homework Statement



A car of mass 1200 kg produces a maximum power of 50 kW. Find the maximum acceleration of the car when it is traveling at 60 mph.
(A). 1.6 m/s2. (B). 0.4 m/s2. (C). 0.7 m/s2. (D). 2 m/s2. (E). 3 m/s2

Homework Equations



P=Fv
F=ma
mph-m/s = (miles x 1.6 x 1000)/3600

The Attempt at a Solution



P=Fv
P=mav
P/mv=a

m/s= (60 x 1.6 x 1000)/ 3600

50000/1200x26.6 = 1.56...
So I'm saying that the anser is 1.6

i think i have done this right however as i no longer have access to the answers i can't tell. If any thing is wrong could you just point me to the area (i.e. equations or numbers)
 
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KESTRELx said:

Homework Statement



A car of mass 1200 kg produces a maximum power of 50 kW. Find the maximum acceleration of the car when it is traveling at 60 mph.
(A). 1.6 m/s2. (B). 0.4 m/s2. (C). 0.7 m/s2. (D). 2 m/s2. (E). 3 m/s2

Homework Equations



P=Fv
F=ma
mph-m/s = (miles x 1.6 x 1000)/3600

The Attempt at a Solution



P=Fv
P=mav
P/mv=a

m/s= (60 x 1.6 x 1000)/ 3600

50000/1200x26.6 = 1.56...
So I'm saying that the anser is 1.6

i think i have done this right however as i no longer have access to the answers i can't tell. If any thing is wrong could you just point me to the area (i.e. equations or numbers)

Your answer is fine.
 

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