Adding and Subtracting vectors; Finding change in velocity

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SUMMARY

The discussion centers on calculating the change in velocity of a cricket ball hit by a batsman. The initial velocity of the ball is 30 m/s towards the batsman, and the final velocity is 50 m/s towards square leg. The correct calculation of the change in velocity (Δv) is determined to be W31°N, contrasting with the incorrect answer of N59°W provided by a participant. The confusion arises from the use of trigonometric functions to determine the angle, highlighting the importance of understanding vector direction in physics.

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ShannonBanana
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Homework Statement



A batsman hits a cricket ball traveling towards him at 30m/s over square leg at 50m/s. If the cricketer is facing north and square leg is west of him, what is the change in velocity of the ball?

Homework Equations



Δv= Final velocity subtract initial velocity.

The Attempt at a Solution



I've attached a picture of my working, so you might be able to see where I've gone wrong. From this diagram, I got correct the final "speed" but not the direction. My answer was Δv=58m/s N59°W, but the answer given says the direction should be W31°N.
I got my answer through tan-1(50/30) or tan-1(opposite over adjacent). To get the answer given, you would have to (by my reckoning) use adjacent over opposite, which doesn't seem to be right. Do I have θ in the right place? And, if so, why?

Thanks for the help :)
 
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ShannonBanana said:
N59°W, but the answer given says the direction should be W31°N.
Aren't they the same?
 
... Are you serious?? Wow, I'm feeling kind of dumb now... Thank you though! :D
 

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