MHB Addition with eight bit 2's complement numbers. [Check my Work]

AI Thread Summary
The discussion focuses on performing arithmetic operations with eight-bit 2's complement numbers, specifically adding the binary numbers 01110101 and 11011110. The calculation results in 01010011, which corresponds to the decimal value of 83. The operation involves adding a positive number (117) and a negative number (-34), effectively calculating 117 - 34. The participant confirms the correctness of the result and inquires about the possibility of a simpler method for the calculation. It is clarified that while the operation results in a carry, there is no arithmetic overflow, affirming the accuracy of the result.
shamieh
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Perform the following operations involving eight-bit 2's complement numbers and indicate whether arithmetic overflow occurs.

1) 01110101 + 11011110.

So I have a +Positive + a -Negative number. So I just added normally, and got the result of 01010011.

I realized before I started the problem I essentially had 117 +(-34) which is really 117 - 34 = 83.

So my result 01010011 = 83. Was there an easier way I could have done this? And, is this correct? It seems logically correct, but I've been known to screw these up. Also, there would be no overflow right?
 
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Your calculation is correct. The operation results in a carry, but no overflow.
 

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