Addition with eight bit 2's complement numbers. [Check my Work]

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SUMMARY

The discussion focuses on the addition of two eight-bit 2's complement numbers: 01110101 (117) and 11011110 (-34). The participant correctly performed the addition, resulting in 01010011, which equals 83. The calculation confirms that there is no arithmetic overflow, as the operation results in a carry but remains within the valid range of eight-bit 2's complement representation.

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  • Understanding of eight-bit 2's complement representation
  • Basic arithmetic operations with binary numbers
  • Knowledge of overflow conditions in binary addition
  • Familiarity with converting binary to decimal
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  • Learn about detecting overflow in signed binary arithmetic
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shamieh
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Perform the following operations involving eight-bit 2's complement numbers and indicate whether arithmetic overflow occurs.

1) 01110101 + 11011110.

So I have a +Positive + a -Negative number. So I just added normally, and got the result of 01010011.

I realized before I started the problem I essentially had 117 +(-34) which is really 117 - 34 = 83.

So my result 01010011 = 83. Was there an easier way I could have done this? And, is this correct? It seems logically correct, but I've been known to screw these up. Also, there would be no overflow right?
 
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Your calculation is correct. The operation results in a carry, but no overflow.
 

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