Additional energy stored in spring

  • Thread starter Thread starter songoku
  • Start date Start date
  • Tags Tags
    Energy Spring
Click For Summary
The discussion revolves around calculating the additional elastic potential energy stored in a spring when it is extended further. A load of 10 N results in an initial extension of 0.04 m, and the question asks for the energy stored when the spring is extended an additional 0.04 m, totaling 0.08 m. The user initially calculated the energy as 0.600 J but found the answer key states it is 0.200 J. Other participants confirm the user's calculation and express agreement with the initial assessment. The conversation highlights confusion over the correct application of the energy formula for springs.
songoku
Messages
2,508
Reaction score
402

Homework Statement


The graph shows the variation with extension x of the load F on a certain spring
upload_2019-1-12_17-3-1.png

A load of 10 N is placed on the spring. How much additional elastic potential energy will be stored in the spring if it is then extended a further 0.040 m?
a. 0.200 J
b. 0.450 J
c. 0.600 J
d. 0.800 J

Homework Equations


F = k x
E = 1/2 k x2

The Attempt at a Solution


Load of 10 N means the extension is 0.04 m and extended further 0.04 m means that the extension is 0.08 m, right?

I got (c) but the answer key is (a) ??

Thanks
 

Attachments

  • upload_2019-1-12_17-3-1.png
    upload_2019-1-12_17-3-1.png
    58.8 KB · Views: 784
  • ccc.png
    ccc.png
    20.1 KB · Views: 347
Physics news on Phys.org
songoku said:

Homework Statement


The graph shows the variation with extension x of the load F on a certain spring
View attachment 237172
A load of 10 N is placed on the spring. How much additional elastic potential energy will be stored in the spring if it is then extended a further 0.040 m?
a. 0.200 J
b. 0.450 J
c. 0.600 J
d. 0.800 J

Homework Equations


F = k x
E = 1/2 k x2

The Attempt at a Solution


Load of 10 N means the extension is 0.04 m and extended further 0.04 m means that the extension is 0.08 m, right?

I got (c) but the answer key is (a) ??

Thanks

I think you are correct.
 
Thank you
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 17 ·
Replies
17
Views
1K
Replies
17
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
Replies
24
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 20 ·
Replies
20
Views
4K
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K