Adiabatic Process: Proving Variation of Gamma

  • Thread starter Thread starter ajayguhan
  • Start date Start date
  • Tags Tags
    Process
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
ajayguhan
Messages
153
Reaction score
1
I know that adibatic process means no heat transfer.

i.e., →PV[itex]\gamma[/itex] =constant.

Where [itex]\gamma[/itex] = 1.4 for diatomic gas, [itex]\gamma[/itex]= 1.6 for monoatomic gas.

My question is how [itex]\gamma[/itex]=Cp/Cv ?

And can we prove theoritcally that [itex]\gamma[/itex] = 1.4 for diatomic gas, [itex]\gamma[/itex]= 1.6 for monoatomic gas.
 
Physics news on Phys.org
ajayguhan said:
I know that adibatic process means no heat transfer.

i.e., →PV[itex]\gamma[/itex] =constant.

Where [itex]\gamma[/itex] = 1.4 for diatomic gas, [itex]\gamma[/itex]= 1.6 for monoatomic gas.

My question is how [itex]\gamma[/itex]=Cp/Cv ?

Gamma is defined as the ratio of the specific heat at constant pressure to the specific heat at constant temperature.

And can we prove theoritcally that [itex]\gamma[/itex] = 1.4 for diatomic gas, [itex]\gamma[/itex]= 1.6 for monoatomic gas.

http://en.wikipedia.org/wiki/Heat_capacity_ratio
 
ajayguhan said:
I know that adibatic process means no heat transfer.

i.e., →PV[itex]\gamma[/itex] =constant.

This equation is only true for an ideal gas undergoing a reversible (i.e., no entropy generation) adiabatic process.

ajayguhan said:
My question is how [itex]\gamma[/itex]=Cp/Cv ?

It is simply a definition for which we found a physical significance (Like work is defined as a force times its displacement).

ajayguhan said:
And can we prove theoritcally that [itex]\gamma[/itex] = 1.4 for diatomic gas, [itex]\gamma[/itex]= 1.6 for monoatomic gas.

Read The simple case of the monatomic gas and Diatomic gas on Theory of heat capacity.
 
Thank you for spending time to clarify my doubts. Your answer helped me.