Adiabatic process - quantum mechanics and thermodynamics

In summary: Yes, but the only eigenstates you have available are the instantaeous ones, especially once you stop modifying your...In summary, an adiabatic process is defined as a gradual change of the Hamiltonian while a diabatic process is a sudden change of the Hamiltonian.
  • #1
spaghetti3451
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A diabatic process is defined as follows:

Rapidly changing conditions prevent the system from adapting its configuration during the process, hence the spatial probability density remains unchanged. Typically there is no eigenstate of the final Hamiltonian with the same functional form as the initial state. The system ends in a linear combination of states that sum to reproduce the initial probability density.

An adiabatic process is defined as follows:

Gradually changing conditions allow the system to adapt its configuration, hence the probability density is modified by the process. If the system starts in an eigenstate of the initial Hamiltonian, it will end in the corresponding eigenstate of the final Hamiltonian.A diabatic process involves a sudden change of the Hamiltonian, while an adiabtic process involves a gradual change of the Hamiltonian.

The word adiabatic, in thermodynamics, is usually reserved for processes that do not involve the exchange of heat between the system and surroundings. Does this use of the word adiabatic have any relation to the use of the word adiabatic in quantum mechanics? How about the word diabatic?
 
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  • #2
Adiabatic is greek and means without transit. In QM it means that there are no transits between eigenstates. In thermodynamics, it means no transit of heat trough the boundaries.
 
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  • #3
DrDu said:
Adiabatic is greek and means without transit. In QM it means that there are no transits between eigenstates. In thermodynamics, it means no transit of heat trough the boundaries.

What does it mean for there to be no transits between eigenstates in the adiabatic limit?

So far as I understand, in the adiabatic limit, the Hamiltonian changes so slowly that, at each instant, the wavefunction is some eigenstate of the instantaneous Hamiltonian.

I don't see how the issue of 'no transits between eigenstates' arises.
 
  • #4
failexam said:
I don't see how the issue of 'no transits between eigenstates' arises.
Sorry, I don't get what you mean.
 
  • #5
DrDu said:
Sorry, I don't get what you mean.

You say that there are no transits between eigenstates in the adiabatic limit.

It would be helpful if you could explain this in more detail.
 
  • #6
failexam said:
What does it mean for there to be no transits between eigenstates in the adiabatic limit?

So far as I understand, in the adiabatic limit, the Hamiltonian changes so slowly that, at each instant, the wavefunction is some eigenstate of the instantaneous Hamiltonian.

I don't see how the issue of 'no transits between eigenstates' arises.
If the system is initially in an eigenstate of the Hamiltonian, in the adiabatic approximation its stays in an eigenstate of the Hamiltonian, even though that Hamiltonian is changing with time. Contrast that to the other extreme, the sudden approximation, where the initial state is mapped unchanged to the eigenstates of the modified Hamiltonian.
 
  • #7
"Rapidly changing conditions prevent the system from adapting its configuration during the process, hence the spatial probability density remains unchanged. Typically there is no eigenstate of the final Hamiltonian with the same functional form as the initial state. The system ends in a linear combination of states that sum to reproduce the initial probability density."
So if the process is diabatic, it ends up in a linear combination of eigenstates. If you do a measurement, you will find the system exclulively in one eigenstate, which may not coincide with the initial one (or into what it has evolved continuously). In this sense you have made a transit from one eigenstate to the other.
 
  • #8
DrDu said:
"Rapidly changing conditions prevent the system from adapting its configuration during the process, hence the spatial probability density remains unchanged. Typically there is no eigenstate of the final Hamiltonian with the same functional form as the initial state. The system ends in a linear combination of states that sum to reproduce the initial probability density."
So if the process is diabatic, it ends up in a linear combination of eigenstates. If you do a measurement, you will find the system exclulively in one eigenstate, which may not coincide with the initial one (or into what it has evolved continuously). In this sense you have made a transit from one eigenstate to the other.

I get that, in the diabatic limit, the wavefunction remains unchanged, but upon measurement of the system (after the sudden shift of the Hamiltonian), the eigenstate measured is not the same as the initial eigenstate. (This is because the wavefunction (after the sudden shift of the Hamiltonian) is in a linear combination of eigenstate of the new Hamiltonian). So, there has been a transition between eigenstates.

But don't you also make a continuous transition from eigenstate to eigenstate (each instantaneous eigenstate belonging to the instantaneous Hamiltonian) when the Hamiltonian changes gradually in the adiabatic limit?
 
  • #9
failexam said:
But don't you also make a continuous transition from eigenstate to eigenstate (each instantaneous eigenstate belonging to the instantaneous Hamiltonian) when the Hamiltonian changes gradually in the adiabatic limit?
Yes, but the only eigenstates you have available are the instantaeous ones, especially once you stop modifying your hamiltonian.
 
  • #10
In the adiabatic limit where the Hamiltonian changes gradually, what determines the evolution of the eigenstates with time?

In other words, say you have two Hamiltonians ##H(t_{0},x)## and ##H(t+\delta t,x)##. Say that the system is in an eigenstate ##\psi(t_{0},x)## of the Hamiltonian ##H(t_{0},x)##.

Now, the Hamiltonian ##H(t+\delta t,x)## can have a multitude of eigenstates ##\psi_{n}(t_{0}+\delta t,x)##.

How do you figure out which of the eigenstates ##\psi_{n}(t_{0}+\delta t,x)## the system has evolved into?
 
  • #11
The main point in the derivation of the adiabatic theorem is that the initial eigenstate is not degenerate and does not become degenerate during time evolution. There is a nice discussion in the book "Quantum Mechanics" by Messiah. A monograph on how to make this as water tight as possible is the book by Stefan Teufel, Adiabatic Perturbation Theory in Quantum Dynamics.
 
  • #12
DrDu said:
The main point in the derivation of the adiabatic theorem is that the initial eigenstate is not degenerate and does not become degenerate during time evolution. There is a nice discussion in the book "Quantum Mechanics" by Messiah. A monograph on how to make this as water tight as possible is the book by Stefan Teufel, Adiabatic Perturbation Theory in Quantum Dynamics.

I am not talking about degeneracy here though.

I was wondering how Nature selects the eigenstate for the new Hamiltonian since the new Hamiltonian might have any number of eigenstates. (These new eigenstates may or may not have the same energy as the old eigenstate, since the Hamiltonian itself has changed with time, and so the energy must also change with time. Am I wrong?)

So, should there not be some criteria used to determine the evolution of the initial eigenstate with time?
 
  • #13
Sure, you need some conditions on the hamiltonian. I think a sufficient condition is that H(t) is of the form ##H_0+\lambda(t) V## where V has to be relative compact with respect to ##H_0## and lambda being sufficiently smooth.
 
  • #14
DrDu said:
Sure, you need some conditions on the hamiltonian. I think a sufficient condition is that H(t) is of the form ##H_0+\lambda(t) V## where V has to be relative compact with respect to ##H_0## and lambda being sufficiently smooth.

What does it mean for ##V## to be relatively compact with respect to ##H_0##?

Why do you think these conditions are sufficient to determine the new eigenstate?
 
  • #15
Let's consider the easier case of V being absolutely compact. Then the absolute value of all the eigenvalues of V is bounded. Then, if ##H_0## has an isolated eigenvalue which is separated by a gap from the rest of the spectrum, ##H_0+\epsilon V## will have an eigenvalue which is nearer to the original eigenvalue than to the rest of the spectrum for sufficiently small ##\epsilon##, or, if epsilon is a smooth function of time, for sufficiently short times.
 

1. What is an adiabatic process in relation to quantum mechanics and thermodynamics?

An adiabatic process is a thermodynamic process in which there is no transfer of heat or matter between a system and its surroundings. In quantum mechanics, this term is used to describe a process in which the energy of a system remains constant while its quantum state changes.

2. How does the concept of adiabatic process relate to the laws of thermodynamics?

The first law of thermodynamics states that energy cannot be created or destroyed, only transferred or converted. In an adiabatic process, there is no transfer of heat energy, so the change in energy of the system must be due to work done on or by the system. This relates to the second law of thermodynamics, which states that in any energy conversion, some energy will be lost as heat. In an adiabatic process, this loss of energy as heat is eliminated.

3. What is the significance of adiabatic processes in quantum mechanics?

In quantum mechanics, adiabatic processes are important because they allow for the manipulation of quantum states without changing the energy of the system. This is useful in many applications, such as quantum computing, where precise control over quantum states is essential.

4. How are adiabatic processes used in practical applications?

Adiabatic processes have a wide range of practical applications, including in the field of refrigeration. In this case, the adiabatic expansion of a gas is used to reduce its temperature, which can then be used to cool a desired environment. Adiabatic processes are also used in the development of new materials, as they allow for precise control over the energy levels of particles.

5. What are the potential drawbacks of adiabatic processes?

While adiabatic processes have many useful applications, they also have some drawbacks. One potential issue is that they can be slow, as the system must be allowed to adjust without any heat exchange. Additionally, in quantum mechanics, adiabatic processes can be sensitive to external influences, making it difficult to maintain precise control over the system.

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