Adjoint Operator: Proving Unique Adjoint Transformation

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The discussion focuses on proving the uniqueness of the adjoint operator T* for a linear transformation T between finite-dimensional inner product spaces V and W. The definition states that T* satisfies the condition ' = for all x in V and y in W. The proof utilizes an orthonormal basis {v_1, ..., v_n} for V, demonstrating that T*(y) can be expressed as T*(y) = ∑_i overline{'} v_i for all y in W, confirming the existence of a unique adjoint transformation.

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  • Understanding of linear transformations and their properties
  • Familiarity with inner product spaces and their definitions
  • Knowledge of orthonormal bases in finite-dimensional vector spaces
  • Basic concepts of linear algebra as presented in Friedberg's textbook
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typhoonss821
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I recently teach myself linear algebra with Friedberg's textbook.
And I have a question about adjoint operator, which is on p.367.

Definition Let T : V → W be a linear transformation where V and W are finite-dimensional inner product spaces with inner products <‧,‧> and <‧,‧>' respectively. A funtion T* : W → V is called an adjoint of T if <T(x),y>' = <x,T*(x)> for all x in V and y in W.

Then ,my question is how to prove that there is a unique adjoint T* of T ?

Can anyone give me some tips ? thanks^^
 
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Assume that there is another adjoint transformation, let's say T**.
 
To show that there exists such a function, let v_1, \ldots , v_n be an orthonormal basis for V, so that x = \sum_i \langle x,v_i\rangle v_i for any x in V then we have for all x in V and y in W:

\langle T(x), y\rangle &#039; = \langle T (\sum_i \langle x,v_i\rangle v_i ), y\rangle &#039;
= \sum_i \langle x, v_i\rangle \langle T(v_i), y\rangle &#039;
= \langle x, \sum_i \overline{ \langle T(v_i),y\rangle &#039;} v_i\rangle
which is in the form that we'd like.

Which shows that T^*(y) = \sum_i \overline{\langle T(v_i),y\rangle &#039;} v_i for all y in W works.
 
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really appreciate^^
 
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