- #1
tourjete
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Homework Statement
A particle of mass m's velocity varies according to bx-n
Find the position as a function of time, setting x = x0 at t=0
Homework Equations
v(x) = bx-n
possibly relevant: f(x) = -b2mnx-2n-1
The Attempt at a Solution
The first part of the question asked me to find the force acting on the particle as a function of x, which I did using the chain rule. I'm a little unclear as to whether I need f(x) to get x(t).
Anyway, here's my attempt at a solution:
dv/dt = (dv/dx)*(dx/dt)
dv/dt = (dv/dx) * v(x)
Both of these quantities are known so I plugged them in and got an expression for dv/dt. I then tried to integrate that expression twice, once to get v(t) and another time to get x(t). However, when I do that I just get the expression times t2/2, which would make x(0) = 0, not x0 as the problem statement gives.
Am I doing this the complete wrong way or am I on the right track and just not understanding calculus?