Here's the problem: We are ascending in an elevator at sea level. Our eardrums feel a 1 percent decrease in pressure per minute. Calculate the upward speed of the elevator. My solution: *I am using the equation p1/p0 = (T1/T0)^(-g/aR), where p1 and p0 are pressure at point 1 and point 0, respectively. *T1 and T0 are temperatures at point 1 and 0, g is acceleration due to gravity, a is the slope of the first gradient layer (Temperature/Altitude), and R is the specific gas constant for air. *In the context of the problem, we know that p1 = .9 p0, T0 = 288.16K (temperature at sea level), g= 9.8 m/s^2, a = -.0065 K/m (from temperature distribution graph in textbook), and R = 287 J/kg K. *Plugging these values into my equation and solving for T1, I get T1 = 282.4382 K. *Since the temp./altitude distribution is a straight line for this region, I know T1 = T0 + a(h-h0). *h0 is zero, so plugging in and solving for h I obtain h = 880 m. *Since this took place in the course of a minute (which is the time for a 10% pressure decrease to occur, according to the problem), the velocity is 880m/min upward. This seems a little fast? Did I do things right? I would appreciate any input! Thanks!