1. The problem statement, all variables and given/known data What is the expected temperature change during one second of a polypropylene solid with mass 0.1 g at 105 degC to air at 20 degC 2. Relevant equations heat transfer: Q= c m (T1-T0) where Q = amount of heat c = specific heat capacity = 1.8 J/g/K m = mass T1-T0 = change in temperature Newton's law thermal cooling: Q = -h.A.dT(t) Q = heat lost h = heat transfer coefficient for polypropylene = 0.2 A = area, small object = approx. 0.5 cm^2 Temperature differential, constant at 105-20 3. The attempt at a solution T1-T0 = Q / c m = Q / 1.8 * 0.1 Therefore: T1-T0 = (-0.2 * 5*10^-5 * 85) / (1.8 * 0.1) = 4.7 * 10^-3 degC i.e. a very very small temperature drop in one second. Does this look right? Thanks.