Understanding AFM Imaging: Protrusions and Troughs

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The discussion focuses on understanding atomic force microscopy (AFM) imaging of protrusions and troughs. The user seeks assistance with specific questions regarding the expected image profiles for a rectangular protrusion and trough, including calculations for height, width, and percentage changes. There is confusion about the implications of the AFM tip's radius and angle on the imaging results, particularly for the third question involving a triangular profile. The user attempts to clarify the geometry of the AFM tip and its operational mode, expressing uncertainty about the resulting image dimensions. Overall, the thread emphasizes the complexities of interpreting AFM images and the need for precise calculations in microscopy.
garyd
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Hi all
I was wondering if someone could have a look at my answer attempts. I am having great trouble with Q.3 so any help would be greatly appreciated.

Figures are attached

Homework Statement




Q1. Sketch expected image profile for rectangular protrusion from an otherwise locally flat surface if the surface is being imaged with an atomic force microscope with a tip end radius of 50nm and vertical sides. (figure 1)

(i) What will the imaged height of the protrusion be?
(ii)What will the imaged width of the protrusion be?
(iii)Calculate % imaged protrusion broadened compared to original

Q2. Sketch profile from rectangular trough (figure 2)

(i) What will the imaged depth of the trough be?
(ii)What will be the imaged width of the trough be?
(iii)Calculate % imaged protrusion narrowed compared to original

Q3.Sketch profile from rectangular trough (figure 3). AFM tip has an end radius of 40nm and an opening angle of 300 to the vertical
 

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No expert. PF doesn't like template being ignored. Never mind in this case. Studied up on your item by looking at googling AFM.
I hope 1 and 2 are ok, they look reasonable to me. Understand r 50 nm horizontally somewhat. Don't fully understand why vertically also r 50 nm.

In 3 I suppose angle 300 means angle 30 degrees ? So tip is equilateral triangle with rounded tip ? And the thing is operated in non-contact mode with a distance of 40 nm between tip and object as in fig 1? In that case it won't go in all that far and image a triangle 220 wide and deep, right ?
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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