Ag mass number 108+1 neutron (mass number 1) = Beta -1

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SUMMARY

The discussion centers on the transformation of Silver (Ag) with mass number 108 when it absorbs a neutron, resulting in the formation of 109Ag, which beta decays to 109Cd. The original claim that this process leads to Mercury (Hg) with mass number 110 is incorrect; instead, it is confirmed that 108Ag decays to Cadmium (Cd). The confusion arises from a potential typo in the textbook "Chemistry: An Atoms Based Approach," which incorrectly states the product as Hg. Key isotopes discussed include 108Ag, 109Ag, and 109Cd, with their respective half-lives and decay processes clearly outlined.

PREREQUISITES
  • Understanding of beta decay and its implications on atomic structure.
  • Familiarity with isotopes and their stability, particularly 108Ag and 109Cd.
  • Knowledge of atomic numbers and how they relate to elemental identity.
  • Basic concepts of nuclear reactions and neutron absorption.
NEXT STEPS
  • Research the decay processes of isotopes, focusing on beta decay mechanisms.
  • Study the stability and half-lives of isotopes, particularly 109Ag and 109Cd.
  • Examine the periodic table for atomic numbers and their significance in nuclear reactions.
  • Explore the implications of neutron absorption in nuclear physics and its effects on isotopic identity.
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Chemistry students, nuclear physicists, and educators seeking clarity on isotopic transformations and decay processes, particularly in the context of beta decay and neutron interactions.

Joseph Palumbo
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TL;DR Summary: Ag mass number 108+1 neutron (mass number 1) =Beta -1

does this equal Cadmium or Mercury? 'Chemistry An Atoms Based Approach' problem 2.97 (c) says the answer is Hg mass number 110
I came up with Cadmium is this a typo?
 
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108Ag is radioactive (half-life 2.39 min), which beta decays to 108Cd.

If 108Ag absorbs a neutron, it would become 109Ag, and there should be a spontaneous emission of a prompt gamma. 109Ag is a stable isotope.

109Cd is unstable and decays by electron capture to 109Ag.

Ag has Z=47, Cd has Z=48, and In has Z=49. Hg has Z = 80, while Au has Z=79. Au has only one stable isotope, 197Au, which when absorbing a neutron becomes 198Au, which decays by beta decay to a stable nuclide 198Hg. In beta decay, a neutron transforms to a proton, electron and antineutrino.

There is no Hg mass number 110. There is 190Hg, which has Z = 80 (80 protons) and N = 110 (110 neutrons), and it is unstable/radioactive with a half-life of 20 min.

https://www.nndc.bnl.gov/nudat3/
 
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I am so sorry everybody for not clearly stating this, here it is more clearly stated: "
What nuclide is produced in the core of a collapsing giant star by each of the following reactions?
(a)
From p.65: “This increase is the result of the decomposition of a neutron into a proton, which remains in the nucleus, and an electron (Beta particle) that is ejected from it. The additional proton results in an increase in atomic number. This holds evidently because the atomic number is the number of protons. Since the atomic number for Mo is 42, then 42+1=43 which is atomic number for Tc.
96Mo + 31n → 96+3*1=96+3=99Mo + -1β → 99Tc
(b)
The number of protons or the atomic number for Tin or Sn was 50, with the expulsion of Beta -1, the number of protons have increased by one therefore the element is no longer Tin but rather atomic number 51, which is Sb ‘Antimony’, the mass number however, which was changed to 121 will remain the same, now it is an isotope of ‘Antimony ‘ instead of Tin.
118Sn + 31n → 118+3*1=118+3=121Sn + -1β → 119Sb

(c) Once more addition of -1 Beta particle increases number of protons, this time by one thus increasing the atomic number thus changing the element from Silver Ag which has 47 protons to 48 protons which is now the atomic number of Cadmium Cd. Mass number 109 remains the same , now it is an isotope of Cadmium.
108Ag + 1n → 109Ag + -1β → 109Cd
"

What I really don't understand is that (a) and (b) are correct, agree with answers in the back of the book but (c)
is not, the book shows Hg that it was transformed into mercury, can any body explain this to me unless of course
it is a typo mistake in which case I really do apologize!
 
'Thank you 'Astronuc' , I think I understand what you said, I will think more about it, again thank you this seems correct!'------Joseph Palumbo
 

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