Ag mass number 108+1 neutron (mass number 1) = Beta -1

AI Thread Summary
The discussion centers on the transformation of silver (Ag) with a mass number of 108 when it absorbs a neutron, leading to confusion over whether it decays into cadmium (Cd) or mercury (Hg). The original problem states that Ag-108 beta decays to Hg-110, but participants argue that it should decay to Cd-109 instead. Ag-108 is radioactive with a half-life of 2.39 minutes, and upon neutron absorption, it becomes stable Ag-109, which beta decays to unstable Cd-109. The thread highlights discrepancies in the textbook answer, suggesting it may be a typographical error. Overall, the discussion emphasizes the importance of understanding nuclear transformations and the correct identification of resulting isotopes.
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TL;DR Summary: Ag mass number 108+1 neutron (mass number 1) =Beta -1

does this equal Cadmium or Mercury? 'Chemistry An Atoms Based Approach' problem 2.97 (c) says the answer is Hg mass number 110
I came up with Cadmium is this a typo?
 
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108Ag is radioactive (half-life 2.39 min), which beta decays to 108Cd.

If 108Ag absorbs a neutron, it would become 109Ag, and there should be a spontaneous emission of a prompt gamma. 109Ag is a stable isotope.

109Cd is unstable and decays by electron capture to 109Ag.

Ag has Z=47, Cd has Z=48, and In has Z=49. Hg has Z = 80, while Au has Z=79. Au has only one stable isotope, 197Au, which when absorbing a neutron becomes 198Au, which decays by beta decay to a stable nuclide 198Hg. In beta decay, a neutron transforms to a proton, electron and antineutrino.

There is no Hg mass number 110. There is 190Hg, which has Z = 80 (80 protons) and N = 110 (110 neutrons), and it is unstable/radioactive with a half-life of 20 min.

https://www.nndc.bnl.gov/nudat3/
 
I am so sorry everybody for not clearly stating this, here it is more clearly stated: "
What nuclide is produced in the core of a collapsing giant star by each of the following reactions?
(a)
From p.65: “This increase is the result of the decomposition of a neutron into a proton, which remains in the nucleus, and an electron (Beta particle) that is ejected from it. The additional proton results in an increase in atomic number. This holds evidently because the atomic number is the number of protons. Since the atomic number for Mo is 42, then 42+1=43 which is atomic number for Tc.
96Mo + 31n → 96+3*1=96+3=99Mo + -1β → 99Tc
(b)
The number of protons or the atomic number for Tin or Sn was 50, with the expulsion of Beta -1, the number of protons have increased by one therefore the element is no longer Tin but rather atomic number 51, which is Sb ‘Antimony’, the mass number however, which was changed to 121 will remain the same, now it is an isotope of ‘Antimony ‘ instead of Tin.
118Sn + 31n → 118+3*1=118+3=121Sn + -1β → 119Sb

(c) Once more addition of -1 Beta particle increases number of protons, this time by one thus increasing the atomic number thus changing the element from Silver Ag which has 47 protons to 48 protons which is now the atomic number of Cadmium Cd. Mass number 109 remains the same , now it is an isotope of Cadmium.
108Ag + 1n → 109Ag + -1β → 109Cd
"

What I really don't understand is that (a) and (b) are correct, agree with answers in the back of the book but (c)
is not, the book shows Hg that it was transformed into mercury, can any body explain this to me unless of course
it is a typo mistake in which case I really do apologize!
 
'Thank you 'Astronuc' , I think I understand what you said, I will think more about it, again thank you this seems correct!'------Joseph Palumbo
 
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