Answer Gold Beta & Alpha Decay Questions

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Discussion Overview

The discussion revolves around the radioactive decay processes of gold (Au), specifically focusing on beta and alpha decay. Participants explore the resulting daughter nuclei from these decay processes, as well as the underlying principles of radioactive decay.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant questions whether all beta decays result in the loss of a neutron and gain of a proton, leading to an increase in atomic number while the mass number remains unchanged.
  • Another participant inquires if all alpha decays result in the loss of two neutrons and two protons, resulting in a different element from the starting one, while beta decay retains the same element.
  • A later reply clarifies that elements are identified by atomic number rather than mass number.
  • Participants discuss the specific isotopes of gold (Au) and mercury (Hg), noting that Au-197 is a stable isotope and Hg-197 is unstable, with the latter decaying back to gold by electron capture.
  • There is mention of the teaching materials possibly presenting isotopes that do not exist in nature, as well as confusion regarding the average atomic masses presented in the context of the decay processes.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the definitions and implications of beta and alpha decay processes. There is no consensus on the accuracy of the initial claims about decay processes, and the discussion remains unresolved regarding the specifics of isotopes and their decay.

Contextual Notes

Participants highlight limitations in the teaching materials, including potential inaccuracies in the isotopes discussed and the average atomic masses presented, which may not align with the actual isotopes of elements.

kirsten_2009
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Homework Statement



Use the periodic table to find the daughter nucleus after a gold nucleus (Au) undergoes beta decay. What would be the result if the gold nucleus had undergone alpha decay instead?

Homework Equations

The Attempt at a Solution




Beta Decay: A=196.96655 Z=80 Au

Alpha Decay: A=192 Z=77 Ir

I have a couple of questions regarding radioactive decay...is it accurate to say that all beta decays for all radioactive elements results in the loss of a neutron and the gain of a proton? So, the element's atomic number increases by 1 but the mass number stays the same? Also, then is it accurate to say that all alpha decay for all elements results in 2 neutrons being loss and 2 protons being loss? So, all alpha decay results in another element different from the starting one? but beta stays the same element? Sorry for all the questions...I'm just not sure I get it. Thanks!


 
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kirsten_2009 said:

Homework Statement



Use the periodic table to find the daughter nucleus after a gold nucleus (Au) undergoes beta decay. What would be the result if the gold nucleus had undergone alpha decay instead?

Homework Equations

The Attempt at a Solution

Beta Decay: A=196.96655 Z=80 Au

Alpha Decay: A=192 Z=77 Ir

I have a couple of questions regarding radioactive decay...is it accurate to say that all beta decays for all radioactive elements results in the loss of a neutron and the gain of a proton? So, the element's atomic number increases by 1 but the mass number stays the same? Also, then is it accurate to say that all alpha decay for all elements results in 2 neutrons being loss and 2 protons being loss? So, all alpha decay results in another element different from the starting one? but beta stays the same element? Sorry for all the questions...I'm just not sure I get it. Thanks!

You get it --- elements are identified by atomic number, not mass.
 
O.k thank-you...so my answer is correct then? Should I round to 197 for Au's mass number?
 
You said, "Z=80." Which element in the periodic table is identified by Z=80?
 
Mercury but it's mass number is not the same as Gold's...? Is this like some "special mercury" that comes from radioactive gold?
 
Had to check a table of isotopes --- Au197 is a "stable" isotope, and its natural abundance is 100% (all naturally occurring gold is 197). Hg197 is an unstable isotope of mercury that decays back to gold by electron capture with a half life around 4 days. You are being taught from a really weird textbook.

They gave you definitions for α and β decay processes: restating them for you, α decay results in a loss of four atomic mass units and two atomic number units; β decay results in no change in mass and an increase of one in atomic number.

The exercise is just intended to get you used to how to skip backward or forward in the periodic table for the two decay processes without regard to whether the specific decays actually occur in nature.

kirsten_2009 said:
Is this like some "special mercury"

It's an isotope --- the teaching materials you're working from may present you with isotopes that don't even exist given that they've already asked you to look at alpha and beta decays of Au197. Iridium and mercury, and neither decay process actually occurs.

The odd numbers you see for atomic mass (196.______) are averages of the isotopic masses x abundances of those masses in a sample of a particular element, so don't let them throw you.
 
Thanks for the help! So really my answer should be...

Beta Decay: A=197 Z=80 Hg

Alpha Decay: A=193 Z=77 Ir
 
Yup.
 

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