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Homework Help: Again, Last one! Find the area of the shaded region!

  1. Aug 10, 2010 #1
  2. jcsd
  3. Aug 10, 2010 #2

    HallsofIvy

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    For (1) the shaded region lies below the graph of [itex]y= x^3+ x^2- 6x[/itex] and above the graph of [itex]y= 6x[/itex] for x between -4 and 0. Its area is given by
    [tex]\int_{-4}^0 [(x^3+ x^2- 6x)- 6x]dx[/tex]

    For (2) the shaded region lies below the graph of [itex]y= -x^4[/itex] and above the graph of [itex]y= x^4- 32[/itex]. Those cross where [itex]y= -x^4= x^4- 32[/itex] or [itex]2x^4= 32[/itex] so that [itex]x^4= 16[/itex]: x= -2 and x= 2. Its area is given by
    [tex]\int_{-2}^2 [-x^4- (x^4- 32)]dx[/tex]
     
    Last edited by a moderator: Aug 11, 2010
  4. Aug 10, 2010 #3

    Mark44

    Staff: Mentor

    Fixed the LaTeX in the first paragraph, some of which wasn't displaying.
     
  5. Aug 11, 2010 #4

    HallsofIvy

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    Thanks, Mark. I had left out a "/" !
     
  6. Aug 13, 2010 #5

    Redbelly98

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    That should be more than enough "hints" for the OP to solve the homework problems.

    Thread locked, thread moved from "Calculus & Analysis" to Homework & Coursework Questions area.
     
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