Homework Help: Again, Last one! Find the area of the shaded region!

1. Aug 10, 2010

femmed0ll

2. Aug 10, 2010

HallsofIvy

For (1) the shaded region lies below the graph of $y= x^3+ x^2- 6x$ and above the graph of $y= 6x$ for x between -4 and 0. Its area is given by
$$\int_{-4}^0 [(x^3+ x^2- 6x)- 6x]dx$$

For (2) the shaded region lies below the graph of $y= -x^4$ and above the graph of $y= x^4- 32$. Those cross where $y= -x^4= x^4- 32$ or $2x^4= 32$ so that $x^4= 16$: x= -2 and x= 2. Its area is given by
$$\int_{-2}^2 [-x^4- (x^4- 32)]dx$$

Last edited by a moderator: Aug 11, 2010
3. Aug 10, 2010

Staff: Mentor

Fixed the LaTeX in the first paragraph, some of which wasn't displaying.

4. Aug 11, 2010

HallsofIvy

Thanks, Mark. I had left out a "/" !

5. Aug 13, 2010

Redbelly98

Staff Emeritus
That should be more than enough "hints" for the OP to solve the homework problems.

Thread locked, thread moved from "Calculus & Analysis" to Homework & Coursework Questions area.