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Air Drag & No Drag on a Ball Projected Vertically

  1. Nov 13, 2014 #1
    < Moderator Note -- thread moved from General Physics to Homework Help forum >

    If a ball is projected vertically upwards say with a velocity V.

    Case 1: Without air drag
    Case 2: With air drag

    What will be the difference in v-t graphs and the motion of the ball
    Air drag D=bv (b is a constant,v is velocity)

    I know that in case 1, the velocity decreases as the ball goes up from V to 0.
    ##v=V-gt ##
    ##(y=-mx+c)##
    Hence it will be a straight line with slope -g.
    With air drag will the graph still be a straight line??
     
    Last edited by a moderator: Nov 13, 2014
  2. jcsd
  3. Nov 13, 2014 #2

    PeroK

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    What does the slope of the v-t graph represent? And when is this graph a straight line?
     
  4. Nov 13, 2014 #3
    it is a straight line.. for consrant acceleration, vt graph is a straight line which is inclined... v=-gt+V is a straight line. pls dont say its parabolic.
     
  5. Nov 13, 2014 #4

    PeroK

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    And is there constant acceleration with air drag?
     
  6. Nov 14, 2014 #5
    i got the answer...i was talking about no air drag case...with air drag, after serious integration, i found v(t) and it is a function with exponent and is in terms of terminal velocity...you can close the thread.
     
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