Air is made up of only 2 gases oxygen and nitrogen

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Discussion Overview

The discussion revolves around the composition of air, specifically focusing on the percentages of oxygen and nitrogen based on their molecular weights and the average molecular mass of air. Participants explore the calculations involved in determining these percentages, considering both molecular and mass fractions.

Discussion Character

  • Mathematical reasoning
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant proposes equations based on the molecular weights of oxygen and nitrogen to find their percentages in air.
  • Another participant corrects the initial approach by noting that oxygen and nitrogen are diatomic gases, suggesting the need to adjust the molecular weights used in calculations.
  • A participant revises their equations accordingly and calculates percentages of 75% and 25%, questioning their correctness against a provided answer of 72.5% and 27.5%.
  • There is a clarification about whether the percentages refer to weight or number of molecules, highlighting a potential ambiguity in the problem statement.
  • One participant calculates mass percentages and arrives at values of 27.6% and 72.4%, indicating closeness to the book's answer.
  • Another participant asserts that the 25% and 75% values are correct when considering molar fractions, while the 27.6% and 72.4% values are correct in terms of mass percentage.

Areas of Agreement / Disagreement

Participants express differing views on the correct percentages of oxygen and nitrogen in air, with some supporting the values derived from molar fractions and others advocating for mass percentages. The discussion remains unresolved regarding which interpretation aligns with the "correct" answer provided in the book.

Contextual Notes

The discussion highlights the importance of clarifying whether the percentages refer to molecular counts or mass, which affects the calculations and outcomes. There are also unresolved aspects regarding the assumptions made in the calculations.

Dell
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if air is made up of only 2gases oxygen and nitrogen, and the molecular mass of air is 29g/mol, find the % of each component in the air,

what i thought i should do is make 2 equations,

Mw(O)=16
Mw(N)=14

X*16 + Y*14 = 29 (in 1mol of air)
X + Y = 1

but the solution to this is not possible, i get one as a negative pct

the correct answer is meant to be
72.5%
27.5%
 
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Dell said:
Mw(O)=16
Mw(N)=14

These are atomic weights, not molecular weights.
Remember oxygen and nitrogen are both diatomic gases.
 


thanks, so my equations would go

X*2*16 + Y*2*14 = 29 (in 1mol of air)
X + Y = 1


then i get 75%, 25%
is this correct? the "correct" answer in my book is 72.5% 27.5%
 


Is that 72.5% by weight, or by number of molecules?
 


it actually doesn't say, never thought of that,

is what i got by mol;ecules? how would i make the conversioin
 


got it,,

0.75*28=21g
0.25*32=8g

8/29=27.6%
21/29=72.4%

close enough
 


25% and 75% is a correct answer using 28, 32 and 29 as molar masses and assuming final result must be just molar fraction.

27.6% and 72.4% is a correct answer in terms of mass percentage.


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