Air Balloon ( 5.5 inch diameter) vs Helium gas balloon ( 11 inch diameter )?

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SUMMARY

This discussion compares the physical properties of an air-filled balloon with a diameter of 5.5 inches to a helium-filled balloon with a diameter of 11 inches. The volume of the air balloon is calculated to be 31.68 in³, while the helium balloon's volume is 126.71 in³, resulting in a ratio of 0.25 air molecules for every helium atom. The total mass of the air balloon is determined to be 14.4 grams, which is 3.6 times heavier than the helium balloon, weighing 4 grams. The calculations highlight the significant difference in weight and molecular composition between the two types of balloons.

PREREQUISITES
  • Understanding of basic gas laws and principles
  • Familiarity with atomic mass units and molar calculations
  • Knowledge of the composition of air (80% nitrogen, 20% oxygen)
  • Ability to calculate the volume of a sphere
NEXT STEPS
  • Study the Ideal Gas Law and its applications in real-world scenarios
  • Learn about the properties of gases, including density and buoyancy
  • Explore molar mass calculations for various gases
  • Investigate the effects of pressure and temperature on gas behavior
USEFUL FOR

Students in chemistry or physics, educators teaching gas properties, and anyone interested in the practical applications of gas laws in everyday scenarios.

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Homework Statement


You blow up an ordinary party balloon with air until it has a diameter of 5.5 inches. Your friend blows up another
balloon with helium gas until it has a diameter of 11 inches. Air consists mostly of O2 and N2 molecules, while
helium gas consists of He atoms. Assume the pressure in each balloon is the same.


(a) Compare the number of helium atoms to the total number of O2 and N2 molecules.
(b) Air is about 80 percent nitrogen and 20 percent oxygen. Which balloon weighs more and by how much? (
Hint: Imagine that there are 80 helium atoms in the helium balloon. Calculate the mass, in atomic mass units,
of this amount of helium, and then compare to the mass of the corresponding number of oxygen and nitrogen
molecules).


Homework Equations





The Attempt at a Solution


(A)
For the 5.5 inch balloon the volume is (4/3)*pi*2.75^2 = 31.68in^3
For the 11 inch balloon the volume is (4/3)*pi*5.5^2 = 126.71 in^3

Therefor the ratio of air to Helium is 31.68/126.71 = .25 air molecules for every Helium molecule.

But is wrong answer!



(B)

The atomic mass of Helium is 1 so 4 mols of Helium = 4g
And we know that the 1 mol of air is 80%N and 20%Oxygen so we have .8mols of Nitrogen and .2mols of Oxygen

Oxygen's atomic mass is approx 16 so .2mols of Oxygen = 3.2g
Nitrogen has an atomic mass of approx 14 so .8mols of Nitrogen = 11.2g
The total mass of the air balloon is 3.2 + 11.2 = 14.4g

Therefor the air balloon weighs 3.6 times as much as the helium balloon. (14.4/4)
 
Physics news on Phys.org
Part A: Read the question again. What ratio does the question asks for?

Part B: Can I take it that you got part B correct? The working is pretty much OK.
 

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