Air Pressure and Water Pressure

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vrobins1
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Homework Statement



"At the surface of a freshwater lake the air pressure is 1.1 atm. At what depth under water in the lake is the water pressure 4.5 atm?"



Homework Equations



I used the equation Pgauge = Dgh



The Attempt at a Solution



I converted my atm to Pascals--> (4.5)(100000) = 450000 Pa
Pguage = Dgh
Pguage = (1000)(9.8)(h)

-I used 1000, the density of water, but I'm not sure that is the right info to use for D!

Then I solved for h.

h = 450000/ (10000x9.8)
h = 45.92
I got it incorrect though. Can anyone offer any insight? Thanks!
 
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vrobins1 said:

Homework Statement



"At the surface of a freshwater lake the air pressure is 1.1 atm. At what depth under water in the lake is the water pressure 4.5 atm?"



Homework Equations



I used the equation Pgauge = Dgh



The Attempt at a Solution



I converted my atm to Pascals--> (4.5)(100000) = 450000 Pa
Pguage = Dgh
Pguage = (1000)(9.8)(h)

-I used 1000, the density of water, but I'm not sure that is the right info to use for D!

Then I solved for h.

h = 450000/ (10000x9.8)
h = 45.92
I got it incorrect though. Can anyone offer any insight? Thanks!
That would have been OK if the problem asked for the gauge pressure. I think it's looking for the depth at an absolute pressure of 4.5 atm, which includes the atmospheric pressure.