Air Resistance Force on 1.21 g Samara Falling at 1.1 m/s

[ragbash]

A 1.21 g samara--the winged fruit of a maple tree--falls toward the ground with a constant speed of 1.1 m/s What is the force of air resistance exerted on the samara?
I know that F=ma
I also know I have to account for 9.81 N for g. So by upward force am I looking for W? That would be 11.9N.

 

[skeeter]

correction ...

1.21 g = 0.00121 kg

force of air resistance = mg = (.00121 kg)(9.81 m/s^2) = .0119 N