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## Homework Statement

The problem -

Consider lines L1 and L2:

L1: r1 = (X,Y) = (1,2) + T (6,1)

L2: r2 = (X,Y) = (1,2) + K (4,3)

Find an equation for either of the bisectors of the angles between L1 and L2

## Homework Equations

## The Attempt at a Solution

[tex]cos\alpha = \frac{(a,b)\bullet(4,3)}{\|(a,b)\|\|(4,3)\|}=\frac{(a,b)\bullet(6,1)}{\|(a,b)\|\|(6,1)\|}[/tex]

[tex]\frac{4a+3b}{5}=\frac{6a+b}{6}[/tex]

[tex]a=\frac{13}{6}b[/tex]

I'm not exactly sure what the question is asking, is there anything else I have to do?