- #1

jasonfarley89

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We have E the set of even integers with ordinary addition Define new multiplication * on E defined as

a*b = ab/2 where on the right hand side of the equation is just normal multiplication.

I am just a bit confused i am trying to show Associative multiplication meaning i have to show

(a*b)*c = a*(b*c)

when i do (a*b)*c am i supposed to get (ab/2)(c/2) ?? i feel like i am just doing something really stupid here

Can someone explain? Its binary operation so it can only take two elements at a time right?

also i am bit confused with distributive law,

so a*(b+c) = a(b+c)/2? i want to be equal to (ab)*(ac) = ab(ac)/2 right?

Can someone help please

a*b = ab/2 where on the right hand side of the equation is just normal multiplication.

I am just a bit confused i am trying to show Associative multiplication meaning i have to show

(a*b)*c = a*(b*c)

when i do (a*b)*c am i supposed to get (ab/2)(c/2) ?? i feel like i am just doing something really stupid here

Can someone explain? Its binary operation so it can only take two elements at a time right?

also i am bit confused with distributive law,

so a*(b+c) = a(b+c)/2? i want to be equal to (ab)*(ac) = ab(ac)/2 right?

Can someone help please

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