- #1

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a/b=(x/c)^x

A log approach only yields x*log(x/c)=log (a/b) which really doesn't get me anywhere.

- Thread starter jzimmerm
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- #1

- 1

- 0

a/b=(x/c)^x

A log approach only yields x*log(x/c)=log (a/b) which really doesn't get me anywhere.

- #2

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Well, you won't go very far! This is impossible to solve algebraically.

- #3

HallsofIvy

Science Advisor

Homework Helper

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Should be able to use the Lambert W function- it is defined as the inverse to the function xe^{x}.

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