Algebraic Properties of Matrix Operations

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SUMMARY

The discussion centers on the algebraic properties of matrix operations, specifically addressing the flawed proof that if \( A^2 = AB \) for two non-zero (2x2) matrices A and B, then A must equal B. The error lies in the assumption that the product of matrices being the zero matrix implies one of the factors must be zero. A counterexample is provided using matrices with specific zero entries, demonstrating that the conclusion A = B does not hold universally.

PREREQUISITES
  • Understanding of matrix multiplication and properties
  • Familiarity with the concept of the zero matrix
  • Basic knowledge of algebraic manipulation of matrices
  • Experience with 2x2 matrices and their operations
NEXT STEPS
  • Study the implications of the zero product property in matrix algebra
  • Explore counterexamples in linear algebra to reinforce understanding
  • Learn about the rank and nullity of matrices and their relevance to matrix equations
  • Investigate the conditions under which matrix equations hold true
USEFUL FOR

Students of linear algebra, mathematics educators, and anyone interested in the properties of matrix operations and their implications in proofs.

EV33
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1. Homework Statement

Let A and B be (2x2) matrices such that A^2 = AB and A does not equal the zero matrix O. Find the flaw in the following proof that A = B:

Since A^2 = AB, A^2 - AB = the zero matrix O
Factoring yields A(A-B) = O
Since A does not equal O, it follows that A - B = O.
Therefore, A = B.



3. The Attempt at a Solution

I tried setting up two matrices A and B where A = [ a b, c d] and B = [ e f, g h] and following through on the steps of the proof to see if each of the statements was true. However, I kept finding that they were all true.

Please help.
Thanks.
 
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Problem is, the conclusion is not true for all matrices A and B, even when neither is the zero matrix.

Try playing with matrices that have mostly (but not all) zero entries.
 
EV33 said:
1. Homework Statement

Let A and B be (2x2) matrices such that A^2 = AB and A does not equal the zero matrix O. Find the flaw in the following proof that A = B:

Since A^2 = AB, A^2 - AB = the zero matrix O
Factoring yields A(A-B) = O
Since A does not equal O, it follows that A - B = O.
This is not true. The fact that a product of matrices is 0 does NOT imply one of the factors must be 0.
For example
[tex]\begin{bmatrix}1 & 0 \\ 0 & 0\end{bmatrix}\begin{bmatrix}0 & 0 \\ 1 & 0\end{bmatrix}= \begin{bmatrix}0 & 0 \\ 0 & 0\end{bmatrix}[/tex]
the 0 matrix.

Therefore, A = B.



3. The Attempt at a Solution

I tried setting up two matrices A and B where A = [ a b, c d] and B = [ e f, g h] and following through on the steps of the proof to see if each of the statements was true. However, I kept finding that they were all true.

Please help.
Thanks.
 

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