Algebraic Test For Symmetry....2

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The algebraic tests for symmetry reveal that the function y = x^4 - x^2 + 3 is not symmetric with respect to the x-axis, as shown by the transformation y = -y. However, it is symmetric with respect to the y-axis, confirmed by substituting x with -x. When testing for symmetry with respect to the origin, the function fails this test as well. Overall, the function exhibits y-axis symmetry but not symmetry with respect to the x-axis or the origin. The analysis confirms the function's behavior regarding symmetry properties.
nycmathguy
Homework Statement
Use the algebraic tests to check for
symmetry with respect to both axes and the origin.
Relevant Equations
n/a
Use the algebraic tests to check for
symmetry with respect to both axes and the origin.

y = x^4 - x^2 + 3

Let y = - y

-y = x^4 - x^2 + 3

y = (x^4 - x^2 + 3)/-1

y = -x^4 + x^2 - 3

Not symmetric with respect to the x-axis.

Let x = -x

y = (-x)^4 - (-x)^2 + 3

y = x^4 - x^2 + 3

Symmetric with respect to the y-axis.

Let x = -x and y = -y

-y = (-x)^4 - (-x)^2 + 3

y = (x^4 - x^2 + 3)/-1

y = -x^4 + x^2 - 3

Not symmetric with respect to the origin.
 
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Looks fine.
 
fresh_42 said:
Looks fine.
It feels good to be right.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks

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