Alkene Products: Understanding the Possibilities in E2 Elimination Reactions

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SUMMARY

The discussion centers on the number of alkene products generated during E2 elimination reactions, specifically addressing the formation of stereoisomers. Participants assert that the reaction can yield five distinct products, including two alkenes and their corresponding E and Z stereoisomers. The confusion arises from the potential for a fifth product, which is clarified through logical reasoning about the reaction mechanism. This highlights the complexity of stereochemistry in organic reactions.

PREREQUISITES
  • Understanding of E2 elimination reactions in organic chemistry
  • Knowledge of stereochemistry, specifically E and Z isomerism
  • Familiarity with alkene formation and reaction mechanisms
  • Basic principles of organic reaction pathways
NEXT STEPS
  • Study the mechanisms of E2 elimination reactions in detail
  • Explore stereochemical configurations and their implications in organic synthesis
  • Research the concept of regioselectivity in alkene formation
  • Investigate examples of E2 reactions that yield multiple products
USEFUL FOR

Organic chemistry students, educators, and researchers interested in reaction mechanisms and stereochemistry in alkene synthesis.

leopard
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How man different alkene-products, including stereoisomers, are possible when this molecule reacts in an E2 elimination reaction?

What will happen here is that I leaves the molecule, while a new double bond is created. The new bond can be created on two places, so that we have two different alkenes. We also have two stereoisomers (E and Z) for each of these solutions. I expect the answer to be 4.

However, the correct answer is 5. What's the last product?
 
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leopard said:
The new bond can be created on two places

I was never an organiker, but logic tells me that's not true.
 
Ditto.
 

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