All math statements of the if A then B form?

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Discussion Overview

The discussion centers around the assertion that all mathematical statements can be expressed in the form "If A then B." Participants explore this claim through the lens of formal logic, propositional calculus, and the nature of mathematical axioms and theorems.

Discussion Character

  • Debate/contested
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • Some participants reference a claim that all mathematical statements are of the form "If A then B," questioning its validity.
  • Others argue that every mathematical statement is based on axioms, suggesting that statements implicitly start with "if the axioms are true then."
  • One participant provides examples from propositional calculus to illustrate their point, emphasizing the distinction between tautologies and conditionals.
  • There is a discussion about the nature of "if then" statements, with some asserting that certain axioms do not fit the proposed form.
  • Participants challenge each other's understanding of logical notation and the implications of substituting variables in logical expressions.
  • Some express frustration over perceived misunderstandings and the direction of the conversation, indicating a lack of constructive dialogue.

Areas of Agreement / Disagreement

Participants do not reach a consensus on whether all mathematical statements can be expressed in the form "If A then B." Multiple competing views remain, with some defending the original claim and others providing counterarguments based on formal logic.

Contextual Notes

Limitations in the discussion include varying interpretations of logical notation, the definitions of axioms and theorems, and the distinction between tautologies and conditionals. These factors contribute to the complexity of the debate without resolution.

  • #31
I think we're done here.
 
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  • #32
Yes, everyone seems to agree with HallsOfIvy already, except for one person :smile:
 
  • #33
evagelos said:
Why when you substitute ...b---->a ,by B in ...a---->(b---->a) don't you hide the conditional ...a----->b?While is still there??

Hence...a----->(b----->a) it is not of the (if A then B ) form.
On the contray, it obviously is: A= a, B= (b---->a).

Your example is not very appropriate try to find another one
It was your example, not mine.
 

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