Alpha particles with RBE, energy question

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Homework Help Overview

The discussion revolves around a problem involving alpha particles with a relative biological effectiveness (RBE) of 13 delivering a radiation dose to a patient. The specific questions focus on calculating the dosage in rem and the energy absorbed in millijoules (mJ).

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationship between absorbed dose in rem and energy absorption in mJ, questioning the relevance of RBE in calculating energy.
  • Some participants express confusion regarding the correct units and equations to use for the calculations, particularly in distinguishing between rem and rad.
  • There is discussion about the definition of a rad and its conversion to joules per kilogram, as well as the implications of RBE on energy absorption.

Discussion Status

Participants are actively engaging with the problem, attempting to clarify the calculations and units involved. Some have provided insights into the definitions and relationships between the different measures of radiation dose, while others are seeking confirmation of their calculations. There is no clear consensus yet on the correct approach or final answer.

Contextual Notes

Participants note the importance of understanding the definitions of rem and rad, as well as the role of RBE in the context of energy absorption. There is an emphasis on ensuring that all factors are accounted for in the calculations, particularly the conversion factors between units.

FlipStyle1308
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Homework Statement



Alpha particles with an RBE of 13 deliver a 53 mrad whole-body radiation dose to a 65 kg patient.
(a) What dosage, in rem, does the patient receive?
(b) How much energy is absorbed by the patient (in mJ)?

Homework Equations



dose in rem = dose in rad x RBE

The Attempt at a Solution



I correctly answered part (a), getting 0.689J/kg as my answer. For part (b), I then multipled the answer from (a) by 65kg, which equals 44.785 J, or 44,785 mJ. However, my answer is incorrect. Is there something I am missing? Thanks.
 
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FlipStyle1308 said:

Homework Statement



Alpha particles with an RBE of 13 deliver a 53 mrad whole-body radiation dose to a 65 kg patient.
(a) What dosage, in rem, does the patient receive?
(b) How much energy is absorbed by the patient (in mJ)?

Homework Equations



dose in rem = dose in rad x RBE

The Attempt at a Solution



I correctly answered part (a), getting 0.689J/kg as my answer. For part (b), I then multipled the answer from (a) by 65kg, which equals 44.785 J, or 44,785 mJ. However, my answer is incorrect. Is there something I am missing? Thanks.

My guess is you should be using rads for part b, since that is the measure of the actual energy, while rem is some attempt to quantify the damage caused by a certain amount of energy absorption.
 
Part a) should still be in units of rem so that it is apparent that this is absorbed dose in a human. For part b), the actual energy that is absorbed has nothing to do with the RBE. RBE is only a measure of a tissue's sensitivity to a type of radiation, not an energy (well, except for neutrons which have varying RBEs depending on neutron energy).
 
daveb said:
Part a) should still be in units of rem so that it is apparent that this is absorbed dose in a human. For part b), the actual energy that is absorbed has nothing to do with the RBE. RBE is only a measure of a tissue's sensitivity to a type of radiation, not an energy (well, except for neutrons which have varying RBEs depending on neutron energy).

So what equation should I be using? My book only gives me:
RBE = (dose of 200-kV X-rays necessary to produce a given biological effect)/(dose of a particular type of radiation necessary to produce the same biological effect)
and dose in rem = dose in rad X RBE
 
FlipStyle1308 said:
So what equation should I be using? My book only gives me:
RBE = (dose of 200-kV X-rays necessary to produce a given biological effect)/(dose of a particular type of radiation necessary to produce the same biological effect)
and dose in rem = dose in rad X RBE

It should also give you the definition of a rad as 0.01 Joules per kilogram of mass.

http://www.unc.edu/~rowlett/units/dictR.html
 
OlderDan said:
It should also give you the definition of a rad as 0.01 Joules per kilogram of mass.

http://www.unc.edu/~rowlett/units/dictR.html

Hmm, thanks. So (68.9 rad)(13) = 895.7 J/kg
895.7 J/kg x 65 kg = 58220.5 J = 58220500 mJ?
 
Last edited:
FlipStyle1308 said:
Hmm, thanks. So (68.9 rad)(13) = 895.7 J/kg
895.7 J/kg x 65 kg = 58220.5 J = 58220500 mJ?

There is no 13. 53mrad = 53*.01 mJ/kg (the m in mJ comes from the m in mrad). Multiply that by the body mass and you get mJoules of energy. The RBE of 13 means that this much energy from alpha particles is more damaging than the reference radiation that corresponds to RBE = 1, but it does not change the actual energy absorption.
 
OlderDan said:
There is no 13. 53mrad = 53*.01 mJ/kg (the m in mJ comes from the m in mrad). Multiply that by the body mass and you get mJoules of energy. The RBE of 13 means that this much energy from alpha particles is more damaging than the reference radiation that corresponds to RBE = 1, but it does not change the actual energy absorption.

So my answer should be 3445 mJ? It's still incorrect.
 
FlipStyle1308 said:
So my answer should be 3445 mJ? It's still incorrect.

That is not correct. You left out the factor of 0.01

It is 53 mrad * .01 J/kg/rad * 65 kg
 
  • #10
Oh, so 34.45 mJ?
 
  • #11
Bump, can someone please check my answer?
 
  • #12
FlipStyle1308 said:
Bump, can someone please check my answer?

Do you really need someone to confirm that you multiplied correctly?

OlderDan said:
That is not correct. You left out the factor of 0.01

It is 53 mrad * .01 J/kg/rad * 65 kg
 
  • #13
OlderDan said:
Do you really need someone to confirm that you multiplied correctly?

Sorry, I was running out of attempts on WebAssign, and didn't want to risk it by misinterpreting your advice. Thank you!
 

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