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I have seen proofs that the alternating group A_n cannot have subgroups with index less than n. Ok, but what is the subgroup with index equal to n?
The alternating group A_n cannot have subgroups with an index less than n, as established in group theory. The subgroup with an index equal to n is A_{n-1}, which is isomorphic to several subgroups of A_n, each corresponding to fixing a different element from the set {1, 2, ..., n}. This highlights the structural properties of A_n and its relationship with its subgroups.
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morphism said:A_{n-1}?