Altitude of Satellite Orbit in 4.4 Hours

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Homework Help Overview

The discussion revolves around determining the altitude of a satellite that completes a circular orbit around the Earth in 4.4 hours, utilizing gravitational equations related to orbital mechanics.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the formula T^2 = ((4π^2)(r^3))/GM, questioning unit conversions, particularly the necessity of using seconds for time. There are attempts to calculate the radius and altitude based on the formula, with some participants expressing confusion over the results and the distinction between distance from the Earth's center and altitude.

Discussion Status

The conversation is ongoing, with participants providing insights into unit considerations and clarifying the difference between the calculated distance and the requested altitude. There is acknowledgment of discrepancies between calculated values and expected results, prompting further exploration of the problem.

Contextual Notes

Participants are navigating potential issues with unit conversions and the interpretation of the results, specifically regarding the distinction between the radius and altitude of the satellite.

Robertoalva
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1. At what altitude will a satellite complete a circular orbit of the Earth in 4.4 hours?



Homework Equations



T^2 = ((4π^2)(r^3))/GM

The Attempt at a Solution



Used the equation and plugged all the information, and solved, but for a weird reason it comes wrong, maybe I should convert the hours to minutes?
 
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What units did you use for the quantities in your formula?

G = 6.674*10^-11 m^3/kg*s^2

so time may have to be in seconds rather than minutes.

I don't understand why folks think that the units will take care of themselves when making calculations.
 
cuberoot((((15840seconds)^2)(6.67384E-11 N m^2 Kg^-2)(5.974E24Kg))/(4pi^2)) = r

is that correct?
 
Last edited:
Robertoalva said:
cuberoot((((15840seconds)^2)(6.67384E-11 N m^2 Kg^-2)(5.974E24Kg))/(4pi^2)) = r

is that correct?
That formula looks good.
 
Last edited:
That gives an answer in metres. What distance is that calculating, exactly? The question asks for altitude.
 
I do it, but, the answer that it gives me is totally different from the answer that my practice problem gives
 
the answer that this equation gives me is something like,13632 and the real answer should be 7260 or something approximated
 
Robertoalva said:
the answer that this equation gives me is something like,13632 and the real answer should be 7260 or something approximated
That formula gives you the distance r between the center of the Earth and the satellite. To get the altitude of the satellite you have to subtract the Earth radius from r which gives you the correct answer.
 
thank you!
 
  • #10
Robertoalva said:
thank you!
You're welcome.
 
  • #11
Robertoalva said:
What distance is that calculating, exactly? The question asks for altitude.
the answer that this equation gives me is something like,13632 and the real answer should be 7260 or something approximated
No, I meant what distance does that number represent. I was trying to point out that you were not calculating altitude. Anyway, looks like you have it now.
 

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