Altitude - Why is it a Scalar?

  • Thread starter Thread starter ELLE_AW
  • Start date Start date
  • Tags Tags
    Altitude Scalar
Click For Summary
Altitude is classified as a scalar because it represents only magnitude, specifically the height above sea level, without a directional component. While altitude can be expressed as a single number, it does not indicate direction, such as north or south. The discussion raises the point that negative altitudes exist but do not imply a directional aspect, challenging the strict definition of scalars. Some argue that altitude could be viewed as a one-dimensional vector due to its numerical representation, despite the lack of a meaningful multiplication operation for altitudes. Ultimately, altitude is best understood as a scalar quantity in the context of its definition and usage.
ELLE_AW
Messages
16
Reaction score
0

Homework Statement


How come altitude of a mountain is a scalar?

Homework Equations


Scalars = only magnitude
Vectors = have magnitude & direction

The Attempt at a Solution


- Doesn't altitude of a mountain have both magnitude and direction (direction being measured straight up 90 degrees to the ground?
 
Physics news on Phys.org
Altitude is a single number that gives the height above sea level. It cannot, for example, point to the north-west.
 
  • Like
Likes ELLE_AW
Consider how a negative altitude would be handled. Is that the same as a magnitude and direction? Some people would treat it that way and other people would not.
 
ELLE_AW said:
Scalars = only magnitude
That's the one I would challenge.
It is reasonable to define magnitude (of anything to which the term is fairly applied) to be non-negative, but it is not ok to say a scalar cannot be negative.
Though there is an obvious mapping between a field and a one-dimensional vector space over the field, that does not make them the "same". A field has a defined product operator, ##\times:\mathcal{F\times F\rightarrow F}##, whereas the vectors of a vector space do not in general have a product operator ##\times:\mathcal{V\times V\rightarrow V}##.
Thus, to be able to multiply signed numbers it is necessary to allow that they be neither vectors nor mere magnitudes.

In the specific case of altitudes, multiplying them does not make much sense. So perhaps it is more logical to regard altitude as a one dimensional vector.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 44 ·
2
Replies
44
Views
4K
Replies
12
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
2
Views
1K
Replies
21
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K